Math Problem Statement
P5: Simplify the following Boolean expression. X=A’B’C’D’E’+A’B’CD’E’+A’BCD’E’+A’BC’D’E’+A’B’C’D’E+A’BCD’E+A’BCDE+AB’C’D’E+AB’C’D’E+ABCD’E+ABCDE+AB’CDE
Solution
To simplify the given Boolean expression, we will follow these steps:
Expression:
Step 1: Group terms for simplification
Group terms based on their common literals. Let’s rewrite:
- and
- and
Step 2: Apply simplification rules
-
:
-
remains as is.
-
:
-
remains as is.
-
remains as is.
-
remains as is.
-
remains as is.
-
remains as is.
-
remains as is.
Step 3: Combine simplified terms
The simplified Boolean expression is:
Step 4: Combine further if possible
Inspect for more common terms:
- The terms , , , , and cannot combine further as they differ in too many variables.
- Similarly, , , , and remain distinct.
Final Simplified Expression:
This is the most simplified version of the given Boolean expression.
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Math Problem Analysis
Mathematical Concepts
Boolean Algebra
Simplification of Boolean Expressions
Formulas
Distributive Law
Complement Law
Consensus Theorem
Theorems
Absorption Law
De Morgan's Theorems
Suitable Grade Level
Grades 11-12
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