The expression \( 4(x + 3) \) can be simplified by distributing the 4 across the terms inside the parentheses.

\[
4(x + 3) = 4 \cdot x + 4 \cdot 3 = 4x + 12
\]

So, the simplified form is \( 4x + 12 \).

Would you like more details on distribution or have any further questions?

Here are 5 related questions to explore:

1. What happens if you distribute a negative number instead of 4?
2. How would you factor \( 4x + 12 \) back into \( 4(x + 3) \)?
3. What if you were asked to solve \( 4(x + 3) = 20 \)?
4. How do you apply the distributive property when there are two variables inside the parentheses?
5. Can you expand \( 4(x^2 + 3x + 2) \)?

**Tip:** The distributive property is key for simplifying expressions and solving equations, especially when handling parentheses.

Learn how to simplify the algebraic expression 4(x + 3) by applying the distributive property. This problem demonstrates the step-by-step simplification process, perfect for students in Grades 6-8.

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