Math Problem Statement

Simplify 3√48 + √3 - 2√75 and choose the correct answer from the given options.

Solution

To solve the problem:

Problem: Simplify 348+32753\sqrt{48} + \sqrt{3} - 2\sqrt{75}

  1. Simplify the square roots:

    • 48=163=43\sqrt{48} = \sqrt{16 \cdot 3} = 4\sqrt{3}
    • 75=253=53\sqrt{75} = \sqrt{25 \cdot 3} = 5\sqrt{3}
  2. Rewrite the expression:

    • 348+32753\sqrt{48} + \sqrt{3} - 2\sqrt{75}
    • =3(43)+32(53)= 3(4\sqrt{3}) + \sqrt{3} - 2(5\sqrt{3})
    • =123+3103= 12\sqrt{3} + \sqrt{3} - 10\sqrt{3}
  3. Combine like terms (all are in 3\sqrt{3}):

    • 123+3103=(12+110)3=3312\sqrt{3} + \sqrt{3} - 10\sqrt{3} = (12 + 1 - 10)\sqrt{3} = 3\sqrt{3}

Final Answer:

B. 333\sqrt{3}

Would you like a deeper explanation of any step?


Here are five questions to explore further:

  1. How do you simplify square roots with factors?
  2. Why does 48=43\sqrt{48} = 4\sqrt{3}?
  3. How can we combine terms with the same square root?
  4. What happens when there are no like terms in such expressions?
  5. Can this process be applied to cubic roots as well?

Tip: Always simplify square roots by factoring out perfect squares!

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Math Problem Analysis

Mathematical Concepts

Simplification of radicals
Arithmetic with radicals
Factorization

Formulas

√(a * b) = √a * √b

Theorems

Properties of square roots

Suitable Grade Level

Grades 9-10