You provided the values:

- **Principal (p) = 8,000**
- **Rate of interest (r) = 3.5%** per annum
- **Time (t) = 9 months**

If you're calculating simple interest (SI), the formula is:

\[
SI = \frac{P \times R \times T}{100}
\]

Where:
- \( P \) is the principal amount,
- \( R \) is the annual rate of interest,
- \( T \) is the time period in years.

Since 9 months is equivalent to \( \frac{9}{12} = 0.75 \) years, let's plug in the values:

\[
SI = \frac{8,000 \times 3.5 \times 0.75}{100}
\]

Let me calculate that for you.The simple interest for the given values is **210**.

Would you like further details or have any questions? Here are some related questions to deepen your understanding:

1. How would the interest change if the time period were 1 year instead of 9 months?
2. What is the total amount after adding interest to the principal?
3. How would the interest be different if the rate were 5% instead of 3.5%?
4. How does simple interest differ from compound interest?
5. What happens to the interest if the time period is reduced to 6 months?

**Tip:** When calculating simple interest, always ensure the time period is converted into years for accurate results!

Learn how to calculate simple interest for a principal of 8,000 at an annual interest rate of 3.5% over 9 months. This problem involves converting months to years and applying the simple interest formula. Suitable for students in Grades 6-8.

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