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This is a simple interest problem where the principal $ P $, interest rate $ r $, and time $ t $ are given. The formula to calculate simple interest is:

\[
I = P \times r \times t
\]

However, since the time is given in days, and interest rates are typically expressed annually, we need to adjust the time period into years. 

### Given:
- $ P = 15,000 $ (principal)
- $ r = 8\% = 0.08 $ (interest rate)
- $ t = 180 \text{ days} $

Since we are assuming 365 days in a year, the time in years is:

\[
t = \frac{180}{365} \approx 0.49315 \text{ years}
\]

Now, applying the simple interest formula:

\[
I = 15,000 \times 0.08 \times 0.49315
\]

\[
I = 591.78
\]

So, the simple interest owed is **$591.78**.

Let me know if you need any more details or clarifications! Here are some questions to extend your understanding:

1. What would happen to the interest if the number of days increased to 240?
2. How does changing the interest rate affect the final interest?
3. What if the principal was $20,000 instead of $15,000?
4. How would the interest change if the time period were calculated in months instead of days?
5. What is the difference between simple and compound interest?

### Tip: 
Always remember to convert the time into years when working with annual interest rates!

The principal P is borrowed at a simple interest rate r for a period of time t. Find the simple interest owed for the use of the money. Assume 365 days in a year. Given: P = $15,000, r = 8%, t = 180 days.

Learn how to calculate the simple interest on a principal of $15,000 at an 8% interest rate over a period of 180 days. This problem involves converting time to years and using the simple interest formula. Ideal for Grades 8-10 students.

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