Math Problem Statement
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Explain example simply
Solution
The example you provided discusses a spring-mass system and solves for the motion of the mass after it is released. Here's a simplified explanation:
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Physical Setup:
- A spring with stiffness is hanging vertically.
- A mass of is attached to the spring.
- When the mass is pulled down and released, it oscillates up and down.
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Newton’s Second Law:
- Using , the forces acting on the mass are:
- The spring force: , opposing displacement.
- The net force gives the equation of motion:
- Using , the forces acting on the mass are:
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Second-Order Differential Equation:
- Rearranging, we get:
- Substituting and :
- This is a second-order linear differential equation describing simple harmonic motion.
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Solving the Equation:
- The characteristic equation is:
- Complex roots indicate oscillatory motion. The general solution is: where and are constants determined by initial conditions.
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Initial Conditions:
- At , the displacement , and velocity :
- Substituting these, the constants are found to be:
- At , the displacement , and velocity :
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Particular Solution:
- The specific solution becomes:
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Resulting Motion:
- The mass undergoes simple harmonic motion:
- Amplitude: .
- Frequency: .
- Period: .
- The mass undergoes simple harmonic motion:
In short:
The spring-mass system oscillates with a cosine function, showing periodic, smooth up-and-down motion due to the spring's restoring force.
Do you want more details on any specific step? Here are some related questions:
- What is the significance of the characteristic equation?
- How do the initial conditions influence the solution?
- Why does the motion follow a cosine function?
- What determines the frequency and amplitude of oscillation?
- Can damping or air resistance be included in this type of problem?
Tip: Always check units carefully when substituting values into formulas to avoid calculation errors!
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Math Problem Analysis
Mathematical Concepts
Second-Order Differential Equations
Simple Harmonic Motion
Newton’s Laws of Motion
Formulas
Newton's second law: F = Ma
Equation of motion for a spring: M(d²x/dt²) = -kx
General solution: x(t) = c1 cos(ωt) + c2 sin(ωt)
Theorems
Solution of second-order linear differential equations
Characteristics of harmonic motion
Suitable Grade Level
Undergraduate Level (Physics/Mathematics)
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