Math Problem Statement
- In an electric shaver, the blade moves back and forth over 8 mm in simple harmonic motion, with a frequency of 120 Hz. Find (i) Displacement at t = 0.5 s (ii) the maximum blade speed. (iii) the magnitude of the maximum acceleration of blade
Solution
We can solve this problem using the principles of simple harmonic motion (SHM). Here's the given data:
- Amplitude =
- Frequency =
- Angular frequency
- Time =
The general equation for SHM is: Assuming no phase shift ():
(i) Displacement at
Substitute , , and :
Simplify , which is an integer multiple of : Thus:
(ii) Maximum blade speed
The maximum speed occurs when the blade passes through the equilibrium point, and is given by: Substitute and : Numerically:
(iii) Magnitude of the maximum acceleration of the blade
The maximum acceleration occurs at the extreme positions and is given by: Substitute and : Numerically:
Final Results:
- Displacement at :
- Maximum blade speed:
- Magnitude of maximum acceleration:
Would you like detailed derivations or explanations of any specific steps?
Related Questions:
- How is the displacement in SHM derived?
- Why is the maximum speed proportional to ?
- How does the angular frequency affect the motion in SHM?
- Can the maximum acceleration be used to determine if unknown?
- What is the effect of doubling the frequency on and ?
Tip:
In SHM problems, always determine first, as it governs both speed and acceleration.
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Math Problem Analysis
Mathematical Concepts
Simple Harmonic Motion (SHM)
Trigonometric Functions
Frequency and Angular Frequency
Kinematics in SHM
Formulas
x(t) = A cos(ωt + φ)
v_max = ωA
a_max = ω²A
ω = 2πf
Theorems
Properties of Simple Harmonic Motion
Relationship between Angular Frequency and Linear Motion
Suitable Grade Level
Grades 11-12
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