Math Problem Statement

Solve for x in the given geometry problem involving similar triangles, where triangle FTG is inside triangle FSH, with corresponding sides proportional. Given dimensions: FT = 54, FS = 48, FH = 88, and FG = 6x + 15.

Solution

The given image shows two triangles, FTG\triangle FTG and FSH\triangle FSH, which are likely similar because they share the same angles (the inner triangle FTG\triangle FTG appears to be scaled down proportionally from the larger triangle FSH\triangle FSH).

Here is a step-by-step analysis and solution:

Step 1: Establish Similarity

The two triangles are similar by the Angle-Angle Similarity Theorem, as they share angle FF and have parallel lines, which ensure proportionality.

Step 2: Proportionality of Sides

Since the triangles are similar, the ratios of their corresponding sides are equal. Using the provided side lengths: Side in FTGCorresponding Side in FSH=Other Sides in FTGOther Corresponding Sides in FSH.\frac{\text{Side in } \triangle FTG}{\text{Corresponding Side in } \triangle FSH} = \frac{\text{Other Sides in } \triangle FTG}{\text{Other Corresponding Sides in } \triangle FSH}.

Specifically, we use: FGFH=FTFS=TGSH.\frac{FG}{FH} = \frac{FT}{FS} = \frac{TG}{SH}.

Step 3: Substitute Known Values

From the diagram:

  • FG=6x+15FG = 6x + 15
  • FH=88FH = 88
  • FT=54FT = 54
  • FS=48FS = 48

Using the proportionality: FTFS=FGFH.\frac{FT}{FS} = \frac{FG}{FH}.

Step 4: Solve for xx

Substitute the known values: 5448=6x+1588.\frac{54}{48} = \frac{6x + 15}{88}.

Simplify 5448\frac{54}{48} to 98\frac{9}{8}: 98=6x+1588.\frac{9}{8} = \frac{6x + 15}{88}.

Cross-multiply to eliminate fractions: 9×88=8×(6x+15).9 \times 88 = 8 \times (6x + 15).

Simplify: 792=48x+120.792 = 48x + 120.

Solve for xx: 48x=792120,48x = 792 - 120, 48x=672.48x = 672. x=67248.x = \frac{672}{48}. x=14.x = 14.

Final Answer:

The value of xx is 14.


Would you like me to confirm additional calculations or explain another aspect of the problem? Here are five related questions you might consider:

  1. How do we verify the similarity of triangles using angles?
  2. Can we solve for the remaining side lengths once xx is found?
  3. How does proportionality work in geometric problems?
  4. What is the relationship between scale factors and side lengths?
  5. How can we apply similar triangle properties to real-world scenarios?

Tip: Always simplify fractions in geometry problems early; it makes cross-multiplication much easier to handle.

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Math Problem Analysis

Mathematical Concepts

Geometry
Similar Triangles
Proportionality
Algebra

Formulas

(Side1 of Triangle 1) / (Corresponding Side1 of Triangle 2) = (Side2 of Triangle 1) / (Corresponding Side2 of Triangle 2)

Theorems

Angle-Angle Similarity Theorem

Suitable Grade Level

Grades 8-10