Math Problem Statement

Use sigma notation to write the sum: [3 - (1/7)]^2 + [3 - (2/7)]^2 + ... + [3 - (7/7)]^2

Solution

To express the given sum in sigma notation, let's analyze the pattern in the terms provided:

Each term is of the form: (3j7)2\left(3 - \frac{j}{7}\right)^2 where jj is an integer that increments by 1, starting from j=1j = 1 up to j=7j = 7.

Therefore, the sum can be represented as: j=17(3j7)2\sum_{j=1}^{7} \left(3 - \frac{j}{7}\right)^2

So, the complete answer in sigma notation is: j=17(3j7)2\sum_{j=1}^{7} \left(3 - \frac{j}{7}\right)^2

Would you like more details on how I derived this notation, or do you have any questions?

Here are some related questions to explore further:

  1. What are the properties of sigma notation in summing series?
  2. How can this expression be expanded term-by-term?
  3. What does it mean to square each term inside a summation?
  4. How does changing the upper bound of jj affect the sum?
  5. How could this sum be approximated or simplified for large bounds?

Tip: When writing in sigma notation, always identify a pattern in each term and the range of values for the index to make the expression concise and accurate.

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Math Problem Analysis

Mathematical Concepts

Sigma Notation
Summation
Series
Exponents

Formulas

Summation notation ∑ from j=1 to n
(a - b)^2 expansion

Theorems

Summation Rules

Suitable Grade Level

Grades 9-11