Math Problem Statement

Write the following series in sigma notation. 9, plus, 19, plus, 29, plus, 39, plus, 49 9+19+29+39+49

Solution

The given series 9+19+29+39+499 + 19 + 29 + 39 + 49 follows an arithmetic progression with the first term a1=9a_1 = 9 and the common difference d=10d = 10. To express this in sigma notation, let's identify the general term for the series.

The general term of an arithmetic series is given by: an=a1+(n1)da_n = a_1 + (n-1) \cdot d Substituting a1=9a_1 = 9 and d=10d = 10, the general term becomes: an=9+(n1)10=10n1a_n = 9 + (n-1) \cdot 10 = 10n - 1 Now, we can express the sum in sigma notation for nn from 1 to 5, since there are 5 terms in the series:

n=15(10n1)\sum_{n=1}^{5} (10n - 1)

This is the sigma notation for the given series.

Would you like further details or have any questions?

Here are 5 related questions:

  1. How do you find the sum of an arithmetic series?
  2. Can you express a geometric series in sigma notation?
  3. How is the common difference calculated in an arithmetic progression?
  4. What happens if the common difference in an arithmetic series is negative?
  5. How can sigma notation be applied to represent infinite series?

Tip: Always verify the first few terms by plugging values of nn into the general term formula to check your sigma notation.

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Math Problem Analysis

Mathematical Concepts

Arithmetic Series
Sigma Notation

Formulas

General term of an arithmetic series: a_n = a_1 + (n-1) * d
Sigma notation for an arithmetic series

Theorems

None (basic arithmetic series and sigma notation)

Suitable Grade Level

Grades 9-10