Math Problem Statement

The 6​-ft wall shown here stands 28 ft from the building. Find the length of the shortest straight beam that will reach to the side of the building from the ground outside the wall.

Solution

To find the length of the shortest straight beam that will reach from the ground outside the wall to the side of the building, we need to calculate the hypotenuse of a right triangle, where:

  1. The height of the building is the total height we need to reach, i.e., the distance from the ground to the point on the building where the beam will touch.
  2. The ground distance (base of the triangle) includes the distance from the wall to the building plus the height of the wall.

Step-by-Step Solution:

  1. Define the Variables:

    • Let hh represent the height of the wall, which is 6 feet.
    • Let dd represent the distance from the wall to the building, which is 28 feet.
    • Let xx represent the height on the building where the beam will touch.

    To minimize the length of the beam, we need to find the point on the building that yields the shortest possible beam length.

  2. Formulate the Distance Function:

    • The beam forms the hypotenuse of a right triangle, where one leg is d+hd + h (total horizontal distance from the starting point on the ground to the building), and the other leg is xx (the height on the building).
    • Using the Pythagorean theorem, the length LL of the beam is given by: L=(d+h)2+x2L = \sqrt{(d + h)^2 + x^2}
  3. Differentiate and Solve for the Minimum: We set up an equation to find xx by differentiating LL with respect to xx and solving for the critical point.

After following these steps, we find that the shortest length

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Math Problem Analysis

Mathematical Concepts

Geometry
Optimization
Right Triangles
Pythagorean Theorem

Formulas

L = √((d + h)^2 + x^2)
Differentiation to find minimum values

Theorems

Pythagorean Theorem
Optimization of functions using derivatives

Suitable Grade Level

Grades 10-12