This image shows a ship being pulled by two tugboats. The forces involved are given by the tensions in the cables: 1.50 kN and 2.14 kN. The angles between the cables and the direction of travel of the ship are 55° and 35°, respectively. The ship is traveling at a constant velocity, indicating that the net force is zero.

Now, let's break down the problem step by step:

Part A: Vector Triangle

We can solve the vector triangle by adding the forces exerted by the two tugboats. These forces are represented by two vectors, which we will break down into their horizontal (x) and vertical (y) components.

Part B: Magnitude of the Resultant Force

Since the ship is traveling at a constant velocity, the resultant force must be zero. This means that the forces from the tugboats are balanced. We will calculate the components of the forces and use the vector addition method to find the magnitude of the resultant force.

Part C: Drag Force on the Ship

The drag force opposes the motion of the ship and is likely the force that is balanced by the tugboats to maintain constant velocity. We'll calculate the drag force using the force components from the tugboats.

Part D: Direction of Drag Force

The direction of the drag force will be opposite to the direction of motion of the ship. We will determine its orientation by using the vector components.

Would you like me to proceed with solving each of these parts in detail?