Math Problem Statement

Determine the shear stress transmitting 100kW at 500rpm if the shaft diameter is 80rpm

Solution

To calculate the shear stress transmitted by the shaft, we can use the following formula:

τ=TJr\tau = \frac{T}{J} \cdot r

Where:

  • τ\tau = Shear stress (Pa or N/m²)
  • TT = Torque (Nm)
  • JJ = Polar moment of inertia for a circular shaft = πd432\frac{\pi d^4}{32}
  • rr = Radius of the shaft = d2\frac{d}{2}
  • dd = Diameter of the shaft (in meters)

Given data:

  • Power P=100 kW=100,000 WP = 100 \text{ kW} = 100,000 \text{ W}
  • Shaft speed N=500 rpmN = 500 \text{ rpm}
  • Diameter of shaft d=80 mm=0.08 md = 80 \text{ mm} = 0.08 \text{ m}

Step 1: Calculate the torque TT

The power is related to torque and rotational speed by the formula:

P=Tω1000P = \frac{T \cdot \omega}{1000}

Where:

  • PP = Power (in kW)
  • TT = Torque (in Nm)
  • ω\omega = Angular velocity (in rad/s)

We know that:

ω=2πN60\omega = \frac{2\pi N}{60}

Substitute the values:

ω=2π×50060=1000π6052.36 rad/s\omega = \frac{2\pi \times 500}{60} = \frac{1000\pi}{60} \approx 52.36 \text{ rad/s}

Now, we rearrange the formula to find TT:

T=P1000ω=100000100052.361909.86 NmT = \frac{P \cdot 1000}{\omega} = \frac{100000 \cdot 1000}{52.36} \approx 1909.86 \text{ Nm}

Step 2: Calculate the polar moment of inertia JJ

The polar moment of inertia JJ for a solid circular shaft is:

J=πd432J = \frac{\pi d^4}{32}

Substitute d=0.08 md = 0.08 \text{ m}:

J=π(0.08)4321.256×105 m4J = \frac{\pi (0.08)^4}{32} \approx 1.256 \times 10^{-5} \text{ m}^4

Step 3: Calculate the shear stress

Now, we can calculate the shear stress τ\tau using the formula:

τ=TJr\tau = \frac{T}{J} \cdot r

Where r=d2=0.04 mr = \frac{d}{2} = 0.04 \text{ m}.

Substitute the values:

τ=1909.861.256×1050.0460,743,567 Pa=60.74 MPa\tau = \frac{1909.86}{1.256 \times 10^{-5}} \cdot 0.04 \approx 60,743,567 \text{ Pa} = 60.74 \text{ MPa}

Final Answer:

The shear stress transmitted by the shaft is approximately 60.74 MPa.


Do you want a more detailed explanation of any of the steps? Or have any other questions?

Related Questions:

  1. How does the speed of the shaft affect the shear stress?
  2. What would happen to the shear stress if the shaft diameter increased?
  3. How do you calculate the torque transmitted by a shaft if the power and speed are known?
  4. How does the material of the shaft affect the shear stress?
  5. What is the significance of polar moment of inertia in rotational mechanics?

Tip:

When calculating shear stress in shafts, it’s important to ensure units are consistent (e.g., power in watts, speed in rpm, diameter in meters).

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Math Problem Analysis

Mathematical Concepts

Shear Stress
Torque
Rotational Mechanics
Polar Moment of Inertia

Formulas

Shear stress formula: τ = (T / J) * r
Torque formula: P = (T * ω) / 1000
Angular velocity formula: ω = (2π * N) / 60
Polar moment of inertia formula: J = (π * d^4) / 32

Theorems

Shear stress transmission in shafts
Power and torque relationship

Suitable Grade Level

Grades 11-12