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The given points are:

\[
(-1, 3), \quad (2, 1), \quad (2, -1), \quad (-1, -2)
\]

Let's analyze the coordinates and determine the shape formed by connecting these points in sequence.

1. The points \((-1, 3)\) and \((-1, -2)\) share the same x-coordinate, meaning they are vertically aligned.
2. The points \((2, 1)\) and \((2, -1)\) also share the same x-coordinate, so they are also vertically aligned.
3. The vertical distances between these pairs are:
   - Between \((-1, 3)\) and \((-1, -2)\): the difference in y-coordinates is \(3 - (-2) = 5\).
   - Between \((2, 1)\) and \((2, -1)\): the difference in y-coordinates is \(1 - (-1) = 2\).

Next, we calculate the horizontal distances between:
- The points \((-1, 3)\) and \((2, 1)\): The difference in x-coordinates is \(2 - (-1) = 3\), and the difference in y-coordinates is \(3 - 1 = 2\).
- The points \((-1, -2)\) and \((2, -1)\): Similarly, the difference in x-coordinates is \(2 - (-1) = 3\), and the difference in y-coordinates is \(-2 - (-1) = -1\).

Since the vertical and horizontal distances differ, this set of points forms a **trapezoid**.

Would you like more details or have any questions? 

Here are 5 related questions:
1. What is the formula to find the distance between two points?
2. How can you check if four points form a parallelogram?
3. What are the properties of a trapezoid?
4. Can a trapezoid have right angles?
5. How do you calculate the area of a trapezoid?

**Tip:** When analyzing the shape formed by points on a coordinate plane, checking for equal distances and parallel sides can help identify common quadrilaterals.

Which shape do you get if you plot the given four points (-1, 3), (2, 1), (2, -1), and (-1, -2)?

Explore how to determine the shape formed by four points on a coordinate plane: (-1, 3), (2, 1), (2, -1), and (-1, -2). Using properties of coordinate geometry, this problem leads to the identification of a trapezoid. Suitable for Grades 7-9.

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