The given points are:

$(-1, 3), \quad (2, 1), \quad (2, -1), \quad (-1, -2)$

Let's analyze the coordinates and determine the shape formed by connecting these points in sequence.

1. The points $(-1, 3)$ and $(-1, -2)$ share the same x-coordinate, meaning they are vertically aligned.
2. The points $(2, 1)$ and $(2, -1)$ also share the same x-coordinate, so they are also vertically aligned.
3. The vertical distances between these pairs are:
   • Between $(-1, 3)$ and $(-1, -2)$: the difference in y-coordinates is $3 - (-2) = 5$.
   • Between $(2, 1)$ and $(2, -1)$: the difference in y-coordinates is $1 - (-1) = 2$.

Next, we calculate the horizontal distances between:

• The points $(-1, 3)$ and $(2, 1)$: The difference in x-coordinates is $2 - (-1) = 3$, and the difference in y-coordinates is $3 - 1 = 2$.
• The points $(-1, -2)$ and $(2, -1)$: Similarly, the difference in x-coordinates is $2 - (-1) = 3$, and the difference in y-coordinates is $-2 - (-1) = -1$.

Since the vertical and horizontal distances differ, this set of points forms a trapezoid.

Would you like more details or have any questions?

Here are 5 related questions:

1. What is the formula to find the distance between two points?
2. How can you check if four points form a parallelogram?
3. What are the properties of a trapezoid?
4. Can a trapezoid have right angles?
5. How do you calculate the area of a trapezoid?

Tip: When analyzing the shape formed by points on a coordinate plane, checking for equal distances and parallel sides can help identify common quadrilaterals.