Math Problem Statement

Identical small circles with diameter 1 cm are inside a big one. Find the shaded area.

Solution

To solve this problem, let's go through it step-by-step.

Problem Analysis:

  1. We have identical small circles with a diameter of 1cm1 \, \text{cm}.
  2. These small circles are arranged inside a larger circle.
  3. The task is to find the area of the shaded region between the large circle and the small circles.

Solution Steps:

  1. Calculate the Radius of the Small Circles: Since each small circle has a diameter of 1cm1 \, \text{cm}, its radius rr is: r=12=0.5cmr = \frac{1}{2} = 0.5 \, \text{cm}

  2. Arrangement of the Small Circles in the Large Circle:

    • In this configuration, 7 small circles fit inside the large circle: 6 around the perimeter and 1 in the center.
    • The 6 surrounding circles touch each other and the central circle.
  3. Calculate the Radius of the Large Circle:

    • The distance from the center of the central small circle to the edge of one of the outer small circles is equal to 2 radii of the small circles (the central radius plus one outer radius).
    • Thus, the radius RR of the large circle is: R=2×0.5=1cmR = 2 \times 0.5 = 1 \, \text{cm}
  4. Calculate the Area of the Large Circle:

    • The area AlargeA_{\text{large}} of the large circle with radius R=1cmR = 1 \, \text{cm} is: Alarge=πR2=π×12=πcm2A_{\text{large}} = \pi R^2 = \pi \times 1^2 = \pi \, \text{cm}^2
  5. Calculate the Area of One Small Circle:

    • The area AsmallA_{\text{small}} of each small circle with radius r=0.5cmr = 0.5 \, \text{cm} is: Asmall=πr2=π×(0.5)2=π4cm2A_{\text{small}} = \pi r^2 = \pi \times (0.5)^2 = \frac{\pi}{4} \, \text{cm}^2
  6. Calculate the Total Area of the 7 Small Circles:

    • Since there are 7 small circles, the total area of the small circles is: Asmall total=7×π4=7π4cm2A_{\text{small total}} = 7 \times \frac{\pi}{4} = \frac{7\pi}{4} \, \text{cm}^2
  7. Calculate the Shaded Area:

    • The shaded area is the difference between the area of the large circle and the total area of the small circles: Ashaded=AlargeAsmall totalA_{\text{shaded}} = A_{\text{large}} - A_{\text{small total}} [ A_{\text{shaded}} = \pi - \frac{7\pi}{4} = \frac{4\pi - 7\pi}{4} = -\frac{3\pi}{4}

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Math Problem Analysis

Mathematical Concepts

Geometry
Circle Area
Subtraction of Areas

Formulas

Area of a circle: A = πr^2
Diameter to radius conversion: r = d / 2
Shaded area: A_shaded = A_large - A_small_total

Theorems

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Suitable Grade Level

Grades 9-10