Math Problem Statement

Find the area of the shaded regions below. Give your answer as a completely simplified exact value in terms of π (no approximations).

Solution

To solve the problem, we need to find the area of the shaded regions. Here's the breakdown:


Step 1: Determine the total area of the semicircle

The semicircle has a radius of 4cm4 \, \text{cm}, as given. The formula for the area of a semicircle is: Area of semicircle=12πr2\text{Area of semicircle} = \frac{1}{2} \pi r^2 Substituting r=4r = 4: Area of semicircle=12π(4)2=12π16=8π\text{Area of semicircle} = \frac{1}{2} \pi (4)^2 = \frac{1}{2} \pi \cdot 16 = 8\pi


Step 2: Calculate the area of the triangle MLN\triangle MLN

The triangle MLN\triangle MLN is isosceles with its base LNLN and height OMOM (which is the radius). The angle at OO (central angle) is 9090^\circ, so the triangle splits into two right triangles with angles 4545^\circ.

Each right triangle has:

  • Base = 4cm4 \, \text{cm} (half of the semicircle radius),
  • Height = 4cm4 \, \text{cm}.

The area of one of these right triangles is: Area of one right triangle=12baseheight=1244=8cm2\text{Area of one right triangle} = \frac{1}{2} \cdot \text{base} \cdot \text{height} = \frac{1}{2} \cdot 4 \cdot 4 = 8 \, \text{cm}^2

Since there are two identical right triangles: Area of MLN=28=16cm2\text{Area of } \triangle MLN = 2 \cdot 8 = 16 \, \text{cm}^2


Step 3: Find the area of the shaded regions

The shaded regions are the parts of the semicircle excluding MLN\triangle MLN. Thus: Area of shaded regions=Area of semicircleArea of MLN\text{Area of shaded regions} = \text{Area of semicircle} - \text{Area of } \triangle MLN Substituting: Area of shaded regions=8π16cm2\text{Area of shaded regions} = 8\pi - 16 \, \text{cm}^2


Final Answer:

The area of the shaded regions is: 8π16cm2\boxed{8\pi - 16 \, \text{cm}^2}


Do you have any questions or would you like a more detailed explanation of any step?

Related Questions:

  1. How do you calculate the area of a full circle instead of a semicircle?
  2. Why does the triangle split into two 45°-45°-90° triangles in this problem?
  3. What is the significance of expressing answers in terms of π\pi?
  4. How can we verify the dimensions of the triangle using trigonometry?
  5. If the radius was doubled, how would the shaded area change?

Tip:

Always label all given dimensions and angles clearly in geometric problems to avoid confusion during calculations!

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Math Problem Analysis

Mathematical Concepts

Geometry
Areas of Circles
Triangles
Subtraction of Areas

Formulas

Area of a semicircle: (1/2)πr^2
Area of a triangle: (1/2) × base × height

Theorems

45°-45°-90° Triangle Properties

Suitable Grade Level

Grades 9-10