Math Problem Statement

Find the shaded area in the given geometric figure, which consists of a rectangle (dimensions 6 units x 4 units) and a segment of a semicircle.

Solution

This is an image of a geometry problem where a shaded area lies within a rectangle and is bounded by part of a circle. The rectangle has dimensions 6units×4units6 \, \text{units} \times 4 \, \text{units}, and the shaded region appears to be the area of a circular segment.

We can break this problem into the following steps:

Step 1: Find the area of the rectangle

The total area of the rectangle is: Area of rectangle=length×width=6×4=24square units.\text{Area of rectangle} = \text{length} \times \text{width} = 6 \times 4 = 24 \, \text{square units}.

Step 2: Understand the semicircular part

The shaded area seems to be a circular segment of a circle whose diameter is equal to the width of the rectangle (6units6 \, \text{units}). The circle's radius rr is: r=diameter2=62=3units.r = \frac{\text{diameter}}{2} = \frac{6}{2} = 3 \, \text{units}.

The part of the semicircle included in the shaded region is calculated as:

  • Area of semicircle = 12πr2\frac{1}{2} \pi r^2, and
  • We subtract the triangular area (formed by the straight line).

Let me calculate the exact shaded area mathematically. One moment! sympy as sp

Given values

radius = 3 # radius of the semicircle rect_length = 6 # length of the rectangle rect_width = 4 # width of the rectangle

Area of the rectangle

rect_area = rect_length * rect_width

Area of the semicircle

semi_circle_area = (1 / 2) * sp.pi * radius**2

Triangle dimensions for subtraction (base = 6, height = 4)

triangle_area = (1 / 2) * rect_length * rect_width

Shaded area = semicircle area - triangle area

shaded_area = semi_circle_area - triangle_area

rect_area, semi_circle_area, triangle_area, shaded_area.simplify()Here are the calculations:

  1. Area of the rectangle:
    Area of rectangle=24square units.\text{Area of rectangle} = 24 \, \text{square units}.

  2. Area of the semicircle:
    Area of semicircle=12πr2=12π(32)=4.5πsquare units.\text{Area of semicircle} = \frac{1}{2} \pi r^2 = \frac{1}{2} \pi (3^2) = 4.5\pi \, \text{square units}.

  3. Area of the triangle:
    The triangle's base is 66 and height is 44:
    Area of triangle=12×6×4=12square units.\text{Area of triangle} = \frac{1}{2} \times 6 \times 4 = 12 \, \text{square units}.

  4. Shaded area:
    Shaded area=Area of semicircleArea of triangle=4.5π12square units.\text{Shaded area} = \text{Area of semicircle} - \text{Area of triangle} = 4.5\pi - 12 \, \text{square units}.

Thus, the shaded area is approximately:
Shaded area12+4.5πsquare units.\text{Shaded area} \approx -12 + 4.5\pi \, \text{square units}.

If you want the numerical value, let me compute it! Numerical value of the shaded area shaded_area_numeric = shaded_area.evalf() shaded_area_numericThe shaded area is approximately:
2.14square units.2.14 \, \text{square units}.

Let me know if you'd like further explanation or calculations!

Related Questions:

  1. How do you calculate the area of a segment of a circle directly?
  2. How does the formula for the area of a triangle apply in this problem?
  3. What would happen to the shaded area if the rectangle's dimensions changed?
  4. How is the value of π\pi approximated in practical problems?
  5. How can the concept of integration be applied to find the shaded area?

Tip:

Always sketch and label the geometric shapes in word problems to visualize and simplify the solution process.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Geometry
Areas of Composite Shapes
Circular Segments

Formulas

Area of a rectangle = length × width
Area of a semicircle = (1/2) × π × r^2
Area of a triangle = (1/2) × base × height

Theorems

Properties of circles
Area subtraction for composite shapes

Suitable Grade Level

Grades 9-10