Math Problem Statement

Find C ∪ (B ∩ A'). Write your answer in roster form or as ∅. Sets A, B, and C are subsets of the universal set U. These sets are defined as follows: U = {f, g, h, p, q, r, x, y, z}, A = {g, h, q, r, z}, B = {q, r, x, y, z}, C = {h, p, q, y}.

Solution

Let's analyze the problem step-by-step:

Given Information:

  • U={f,g,h,p,q,r,x,y,z}U = \{ f, g, h, p, q, r, x, y, z \}
  • A={g,h,q,r,z}A = \{ g, h, q, r, z \}
  • B={q,r,x,y,z}B = \{ q, r, x, y, z \}
  • C={h,p,q,y}C = \{ h, p, q, y \}

We are asked to find C(BA)C \cup (B \cap A'), where:

  • AA' is the complement of AA with respect to the universal set UU.
  • BAB \cap A' is the intersection of set BB and the complement of set AA.
  • Finally, we find the union of set CC with BAB \cap A'.

Step 1: Find AA'

The complement of AA (denoted AA') contains elements in UU but not in AA: A=UA={f,p,x,y}A' = U \setminus A = \{ f, p, x, y \}

Step 2: Find BAB \cap A'

The intersection of BB and AA' includes elements that are in both BB and AA': BA={x,y}B \cap A' = \{ x, y \}

Step 3: Find C(BA)C \cup (B \cap A')

Now, we find the union of CC and BAB \cap A': C(BA)={h,p,q,y}{x,y}={h,p,q,x,y}C \cup (B \cap A') = \{ h, p, q, y \} \cup \{ x, y \} = \{ h, p, q, x, y \}

Conclusion:

The correct answer is C(BA)={h,p,q,x,y}C \cup (B \cap A') = \{ h, p, q, x, y \}.

If this was your attempt, you missed no elements, and the solution is correct. The answer provided in the input box matches the correct set.

Would you like any additional details or clarification? Here are five follow-up questions that might interest you:

  1. What is the difference between the complement and the intersection of sets?
  2. How do you calculate the union of two sets?
  3. Can the complement of a set ever have elements that are also in the set itself?
  4. What are some practical applications of set operations in computing or logic?
  5. How does the size of the universal set affect set operations?

Tip: Always double-check which set operation you need to perform first—parentheses in set expressions work just like in algebra, defining the order of operations.

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Math Problem Analysis

Mathematical Concepts

Set Theory
Union of Sets
Intersection of Sets
Complement of a Set

Formulas

A' = U \setminus A
B ∩ A' = Elements in both B and A'
C ∪ (B ∩ A') = Elements in C or in B ∩ A'

Theorems

Basic Set Operations

Suitable Grade Level

Grades 10-12