Math Problem Statement

3. Misalkan X = {1, 2}, Y = {a} dan Z = {α, β}. Daftarkan anggota-anggota dari masing-masing himpunan: a. - X × Y × Z b. X × X × X × X × X 4. Tentukan himpunan kuasa dari himpunan {∅, {∅}} dan tentukan berapa banyak elemen pada himpunan P({∅, a, {a}, {{a}}})?

Solution

The image contains two mathematical problems in Indonesian related to set theory. Here's a transcription and solution for each:

3. Misalkan X={1,2}X = \{1, 2\}, Y={a}Y = \{a\}, dan Z={α,β}Z = \{\alpha, \beta\}. Daftarkan anggota-anggota dari masing-masing himpunan:

a. X×Y×Z- X \times Y \times Z
b. X×X×X×X×XX \times X \times X \times X \times X

a. X×Y×Z- X \times Y \times Z

This problem involves the Cartesian product of the sets XX, YY, and ZZ. The Cartesian product X×Y×ZX \times Y \times Z contains all ordered triples formed by taking one element from each set.

  • X={1,2}X = \{1, 2\}
  • Y={a}Y = \{a\}
  • Z={α,β}Z = \{\alpha, \beta\}

The Cartesian product is:

X×Y×Z={(1,a,α),(1,a,β),(2,a,α),(2,a,β)}X \times Y \times Z = \{(1, a, \alpha), (1, a, \beta), (2, a, \alpha), (2, a, \beta)\}

b. X×X×X×X×XX \times X \times X \times X \times X

This is the Cartesian product of XX with itself five times, forming ordered 5-tuples:

  • X={1,2}X = \{1, 2\}

Each element of X×X×X×X×XX \times X \times X \times X \times X is a 5-tuple where each component is either 1 or 2. There are 25=322^5 = 32 such tuples, and they are:

{(1,1,1,1,1),(1,1,1,1,2),,(2,2,2,2,1),(2,2,2,2,2)}\{(1, 1, 1, 1, 1), (1, 1, 1, 1, 2), \dots, (2, 2, 2, 2, 1), (2, 2, 2, 2, 2)\}

4. Tentukan himpunan kuasa dari himpunan {,{}}\{\emptyset, \{\emptyset\}\} dan tentukan berapa banyak elemen pada himpunan P({,a,{a},{{a}}})P (\{\emptyset, a, \{a\}, \{\{a\}\}\})?

a. Power Set of {,{}}\{\emptyset, \{\emptyset\}\}

The power set of a set contains all its subsets, including the empty set and the set itself.

For A={,{}}A = \{\emptyset, \{\emptyset\}\}, the subsets are:

P(A)={,{},{{}},{,{}}}\mathcal{P}(A) = \{\emptyset, \{\emptyset\}, \{\{\emptyset\}\}, \{\emptyset, \{\emptyset\}\}\}

So, the power set has 4 elements.

b. P({,a,{a},{{a}}})P (\{\emptyset, a, \{a\}, \{\{a\}\}\})

We need to find the number of elements in the power set of B={,a,{a},{{a}}}B = \{\emptyset, a, \{a\}, \{\{a\}\}\}. The number of elements in a power set is given by 2n2^n, where nn is the number of elements in the set.

Here, BB has 4 elements, so:

P(B)=24=16|\mathcal{P}(B)| = 2^4 = 16

Thus, the power set has 16 elements.


Would you like more details or have any questions? Here are 5 related questions:

  1. How is the Cartesian product defined for two or more sets?
  2. What is the significance of the empty set \emptyset in set theory?
  3. How do you determine the number of elements in a Cartesian product?
  4. What is the power set, and how is it calculated for a given set?
  5. How do subsets relate to the original set in set theory?

Tip: When calculating power sets, remember that each element of a set either belongs or doesn’t belong to a subset, which leads to 2n2^n possibilities for a set of size nn.

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Math Problem Analysis

Mathematical Concepts

Set Theory
Cartesian Product
Power Set

Formulas

Cartesian Product: X × Y × Z
Power Set: 2^n

Theorems

Power Set Theorem

Suitable Grade Level

Grades 9-11