Math Problem Statement

Perform algebraic set operations in the formulated problems for sets A, B, and C.

Solution

Let's break down and solve each part of the problem presented in the image:

Part (i)

We are given the following information:

  • A=72|A| = 72 (the cardinality of set AA),
  • B=28|B| = 28 (the cardinality of set BB),
  • AB=13|A \cap B| = 13 (the cardinality of the intersection of sets AA and BB).

We are asked to find the cardinality of ABA \cup B (the union of sets AA and BB).

The formula for the cardinality of the union of two sets is: AB=A+BAB|A \cup B| = |A| + |B| - |A \cap B|

Substituting the values we have: AB=72+2813=87|A \cup B| = 72 + 28 - 13 = 87

Thus, the cardinality of ABA \cup B is 87.


Part (ii)

We are given:

  • AB=45|A - B| = 45 (the cardinality of the difference between sets AA and BB),
  • AB=110|A \cup B| = 110,
  • AB=15|A \cap B| = 15.

We are asked to find B|B|, the cardinality of set BB.

We know the formula for the cardinality of the difference between two sets: AB=AAB|A - B| = |A| - |A \cap B| Thus, solving for A|A|: A=AB+AB=45+15=60|A| = |A - B| + |A \cap B| = 45 + 15 = 60

Now, using the formula for the union of two sets: AB=A+BAB|A \cup B| = |A| + |B| - |A \cap B| Substituting the known values: 110=60+B15110 = 60 + |B| - 15 Simplifying: 110=45+B110 = 45 + |B| B=11045=65|B| = 110 - 45 = 65

Thus, the cardinality of set BB is 65.


Part (iii)

We are given:

  • A=33|A| = 33,
  • B=36|B| = 36,
  • C=28|C| = 28,
  • We are asked to find ABC|A \cup B \cup C|.

The general formula for the union of three sets is: ABC=A+B+CABBCAC+ABC|A \cup B \cup C| = |A| + |B| + |C| - |A \cap B| - |B \cap C| - |A \cap C| + |A \cap B \cap C| However, from the image and the problem statement, it seems like we're dealing with the Venn diagram to help us find the correct values for the intersections of the sets. Specifically, the diagram shows the overlapping areas of the three sets.

From the diagram, we can use the following intersections:

  • AB=5|A \cap B| = 5,
  • BC=10|B \cap C| = 10,
  • AC=15|A \cap C| = 15,
  • ABC=5|A \cap B \cap C| = 5.

Now, applying the formula: ABC=33+36+2851015+5|A \cup B \cup C| = 33 + 36 + 28 - 5 - 10 - 15 + 5 Simplifying: ABC=9730+5=72|A \cup B \cup C| = 97 - 30 + 5 = 72

Thus, the cardinality of ABCA \cup B \cup C is 72.


Do you need further explanation or details? Here are some related questions:

  1. How is the cardinality of intersections of more than two sets derived?
  2. What are the general properties of set operations like union and intersection?
  3. How can a Venn diagram visually assist in solving problems involving three sets?
  4. Can we apply similar methods to solve set operations with more than three sets?
  5. How do we interpret ABA - B in the context of a Venn diagram?

Tip: Always remember to apply the principle of inclusion and exclusion when calculating the union of multiple sets.

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Math Problem Analysis

Mathematical Concepts

Set Theory
Cardinality
Union and Intersection
Venn Diagrams

Formulas

|A ∪ B| = |A| + |B| - |A ∩ B|
|A - B| = |A| - |A ∩ B|
|A ∪ B ∪ C| = |A| + |B| + |C| - |A ∩ B| - |B ∩ C| - |A ∩ C| + |A ∩ B ∩ C|

Theorems

Principle of Inclusion-Exclusion

Suitable Grade Level

Grades 9-12