Math Problem Statement

x\in s:can:\left{x\right}=s:

Solution

It looks like you're trying to express a mathematical statement about sets and elements. However, the notation needs a bit of clarification. Here's my interpretation of what you might be asking:

You have:

  • xsx \in s, meaning that xx is an element of the set ss.
  • Then you're asking whether {x}=s\{ x \} = s, meaning whether the set containing xx is equal to the set ss.

Breaking it down:

  1. xsx \in s: This means that xx is an element of the set ss, i.e., xx is one of the objects contained in the set ss.

  2. {x}=s\{ x \} = s: The set {x}\{ x \} is a set that contains the element xx alone. This would be equal to the set ss only if ss contains exactly xx and no other elements.

So, the statement {x}=s\{ x \} = s holds if and only if s={x}s = \{ x \}. In other words, for this to be true, the set ss must be the set that only contains xx as its sole element.

Example:

  • If s={3}s = \{ 3 \} and x=3x = 3, then xsx \in s and {x}={3}\{ x \} = \{ 3 \}, so {x}=s\{ x \} = s.
  • But if s={3,5}s = \{ 3, 5 \}, then {x}={3}\{ x \} = \{ 3 \} would not be equal to ss unless xx were specifically 33 and the set ss only contained that one element.

Would you like further clarification on set theory, or do you have additional questions on this topic?

Here are some questions that might expand on this:

  1. What does it mean for two sets to be equal?
  2. How do you express "subset" relationships in set theory?
  3. What happens when a set contains other sets as its elements?
  4. How does set membership differ from set inclusion?
  5. Can a set contain itself, and if so, under what conditions?

Tip: Always remember that {x}\{ x \} is a set containing the element xx, whereas xsx \in s refers to xx being one of the elements in ss.

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Math Problem Analysis

Mathematical Concepts

Set Theory
Element Membership
Set Equality

Formulas

-

Theorems

Set Equality Theorem

Suitable Grade Level

Grades 9-12