Math Problem Statement

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Describe the behavior of the series \( \sum_{n=0}^\infty \frac{1}{2} \cdot 1^n \).

Solution

To analyze the series n=0121n\sum_{n=0}^\infty \frac{1}{2} \cdot 1^n:

Series Expression

n=0121n\sum_{n=0}^\infty \frac{1}{2} \cdot 1^n

This simplifies to: n=012\sum_{n=0}^\infty \frac{1}{2} since 1n=11^n = 1 for all nn.

Behavior of the Series

The series becomes: n=012=12+12+12+\sum_{n=0}^\infty \frac{1}{2} = \frac{1}{2} + \frac{1}{2} + \frac{1}{2} + \cdots

This is an infinite series where each term is constant (12\frac{1}{2}). Such a series does not converge because the partial sums grow indefinitely: S_N = \frac{1}{2}N \quad \text{(where N is the number of terms in the partial sum)}.

Conclusion

The series diverges because the terms do not decrease and the partial sums approach infinity.

Would you like me to explain this in further detail or analyze a related case?


Here are 5 related questions for exploration:

  1. What happens if the terms of the series decrease geometrically (e.g., 12n\frac{1}{2^n}) instead of staying constant?
  2. How can you determine if a series converges or diverges in general?
  3. What is the role of the ratio test in evaluating series convergence?
  4. How does the divergence test apply to this series specifically?
  5. What are some examples of conditionally convergent series?

Tip: Always check the behavior of the general term of a series as nn \to \infty to get an idea about convergence or divergence.

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Math Problem Analysis

Mathematical Concepts

Series
Convergence and Divergence
Infinite Series

Formulas

\( S = \sum_{n=0}^\infty a_n \)
\( S_N = \sum_{n=0}^{N} a_n \) (Partial Sum)

Theorems

Test for Divergence

Suitable Grade Level

Grades 11-12 (Advanced High School) or Early Undergraduate