Math Problem Statement

Examine the convergence of the series ∑ (cos(1)/n) from n=1 to infinity.

Solution

To analyze the convergence of the series

n=1cos(1)n,\sum_{n=1}^\infty \frac{\cos(1)}{n},

we note that the term cos(1)\cos(1) is a constant, independent of nn. Hence, the series can be written as:

cos(1)n=11n.\cos(1) \sum_{n=1}^\infty \frac{1}{n}.

The convergence of the series depends on the behavior of n=11n\sum_{n=1}^\infty \frac{1}{n}, which is the harmonic series.

Convergence Analysis:

The harmonic series n=11n\sum_{n=1}^\infty \frac{1}{n} diverges. This means that as nn \to \infty, the partial sums of the series grow without bound. Since multiplying a divergent series by a constant cos(1)\cos(1) does not change its divergence, the given series also diverges.

Conclusion:

The series n=1cos(1)n\sum_{n=1}^\infty \frac{\cos(1)}{n} diverges.

Would you like further explanation or details about series convergence?

Here are five related questions to explore:

  1. What is the harmonic series, and why does it diverge?
  2. How does the comparison test apply to determine series convergence or divergence?
  3. What happens if we replace cos(1)\cos(1) with a variable term depending on nn?
  4. Can we determine if n=1cos(1)n\sum_{n=1}^\infty \frac{\cos(1)}{n} converges absolutely or conditionally?
  5. What role do p-series play in evaluating convergence?

Tip: A good rule to remember is that the harmonic series n=11n\sum_{n=1}^\infty \frac{1}{n} diverges, even though its terms tend to zero.

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Math Problem Analysis

Mathematical Concepts

Series Convergence
Harmonic Series
Constant Multiplication

Formulas

∑ (cos(1)/n)
Harmonic series: ∑ (1/n)

Theorems

Divergence of the Harmonic Series

Suitable Grade Level

Grades 11-12