Math Problem Statement
Solution
The image contains a set of problems on Sequence and Series and Simple Interest and Compound Interest. I will provide step-by-step solutions for a few of the questions.
Let's start with the first question from Sequence and Series:
1. Which term of the series in 6, 312½, … is –19?
This appears to be an arithmetic progression (AP). The nth term of an AP can be given by the formula:
Where:
- is the first term,
- is the common difference,
- is the term number,
- is the nth term.
Step 1: Identify the first term and common difference.
- The first term .
- The second term is , or 312.5.
To find the common difference :
Step 2: Use the nth term formula to find when .
We are given . Plugging in the values:
Simplify the equation:
Since is approximately 1 (we expect an integer value), this suggests the term is very close to the first one but technically a fractional or zero term.
Would you like to solve another question or go into more detail about this one? Here are five related questions:
- How can we verify the common difference in arithmetic progressions?
- What are the conditions for an arithmetic progression to have a negative term?
- Can you explain how to find the sum of an arithmetic series?
- What happens when the common difference is a fraction?
- How would the solution change if we worked with a geometric series?
Tip: Always check if the series is arithmetic (constant difference) or geometric (constant ratio) before applying formulas.
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Math Problem Analysis
Mathematical Concepts
Sequences and Series
Arithmetic Progression (AP)
Geometric Progression (GP)
Simple Interest
Compound Interest
Formulas
nth term of an AP: a_n = a + (n - 1)d
Sum of AP: S_n = n/2 * (2a + (n - 1)d)
nth term of a GP: a_n = ar^(n-1)
Sum of GP: S_n = a(1 - r^n)/(1 - r)
Simple Interest: SI = PRT/100
Compound Interest: A = P(1 + R/100)^T
Theorems
Arithmetic Series Theorem
Geometric Series Theorem
Interest Calculation Theorems
Suitable Grade Level
Grades 10-12
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