Math Problem Statement

F.Sc.I Math CH # 1.docx

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long qno3

Solution

It looks like you want help with the long question number 3 from the document you've uploaded. Here's the specific long question extracted from the file:

Qno3:

  • Separate x+iyxiy\frac{x+iy}{x-iy} into real and imaginary parts.

Let’s work on separating the real and imaginary components of the given complex expression:

Expression:

x+iyxiy\frac{x+iy}{x-iy}

Step 1: Multiply the numerator and denominator by the conjugate of the denominator.

The conjugate of xiyx - iy is x+iyx + iy. Multiplying both the numerator and denominator by this conjugate:

x+iyxiy×x+iyx+iy=(x+iy)(x+iy)(xiy)(x+iy)\frac{x+iy}{x-iy} \times \frac{x+iy}{x+iy} = \frac{(x+iy)(x+iy)}{(x-iy)(x+iy)}

Step 2: Simplify the denominator.

Using the difference of squares formula:

(xiy)(x+iy)=x2(iy)2=x2(y2)=x2+y2(x-iy)(x+iy) = x^2 - (iy)^2 = x^2 - (-y^2) = x^2 + y^2

So the denominator becomes x2+y2x^2 + y^2.

Step 3: Simplify the numerator.

(x+iy)(x+iy)=x2+2ixy+i2y2=x2+2ixyy2(x+iy)(x+iy) = x^2 + 2ixy + i^2y^2 = x^2 + 2ixy - y^2

Thus, the expression becomes: x2y2+2ixyx2+y2\frac{x^2 - y^2 + 2ixy}{x^2 + y^2}

Step 4: Separate into real and imaginary parts.

Now, split the fraction into real and imaginary components:

x2y2x2+y2+i2xyx2+y2\frac{x^2 - y^2}{x^2 + y^2} + i \frac{2xy}{x^2 + y^2}

Thus, the real part is: x2y2x2+y2\frac{x^2 - y^2}{x^2 + y^2} And the imaginary part is: 2xyx2+y2\frac{2xy}{x^2 + y^2}

This is the expression separated into real and imaginary parts.

Would you like further explanation or details on any step?


Here are 5 related questions to expand on this concept:

  1. How do you find the conjugate of a complex number?
  2. What are the properties of the difference of squares used in simplifying complex expressions?
  3. How would you express a complex number in polar form?
  4. Can you provide an example of simplifying a different complex fraction?
  5. What is the geometric interpretation of the division of two complex numbers?

Tip: Always check if you can multiply by a conjugate when simplifying fractions involving complex numbers. It makes the denominator real, which simplifies the expression.

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Math Problem Analysis

Mathematical Concepts

Complex Numbers
Algebra
Imaginary Numbers

Formulas

Conjugate: \( z = x + iy \), \( \text{conjugate}(z) = x - iy \)
Difference of Squares: \( a^2 - b^2 = (a - b)(a + b) \)

Theorems

Conjugate Rule
Difference of Squares Theorem

Suitable Grade Level

Undergraduate or Advanced High School