Math Problem Statement

Determina se la seguente funzione sono relative a X o meno. In caso affermativo affermane il dominio e descrivile

Determina se la seguente funzione sono relative a X o meno. In caso affermativo affermane il dominio e descrivile

Solution

The given graph shows a semicircle centered at the origin with a radius of 1. This type of graph corresponds to the equation of a circle.

For a circle centered at the origin (0,0)(0, 0) with radius rr, the equation is: x2+y2=r2x^2 + y^2 = r^2

Given the graph, the radius r=1r = 1, thus the equation of the full circle is: x2+y2=1x^2 + y^2 = 1

Since the graph shows only the upper semicircle, we need to consider only the positive values of yy. Therefore, the equation representing the upper semicircle is: y=1x2y = \sqrt{1 - x^2}

Determining the Domain

The domain of this function includes all xx values for which the expression under the square root is non-negative: 1x201 - x^2 \geq 0 x21x^2 \leq 1 1x1-1 \leq x \leq 1

Thus, the domain of the function y=1x2y = \sqrt{1 - x^2} is: [1,1][-1, 1]

Summary

  • The function y=1x2y = \sqrt{1 - x^2} describes the upper semicircle.
  • The domain of this function is [1,1][-1, 1].

Would you like more details or have any questions?

Here are some related questions you might find interesting:

  1. What is the range of the function y=1x2y = \sqrt{1 - x^2}?
  2. How would the graph change if the equation were y=1x2y = -\sqrt{1 - x^2}?
  3. What is the area of the semicircle described by y=1x2y = \sqrt{1 - x^2}?
  4. How do you derive the equation of a circle from its geometric properties?
  5. What would be the equation and graph of a semicircle centered at (h,k)(h, k) with radius rr?

Tip

When analyzing functions, always start by identifying their type, which helps in determining their key properties such as domain, range, and behavior.

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Math Problem Analysis

Mathematical Concepts

Geometry
Algebra

Formulas

x^2 + y^2 = r^2
y = sqrt(1 - x^2)

Theorems

-

Suitable Grade Level

High School