Math Problem Statement

x2+y2=1

Solution

The equation you provided, x2+y2=1x^2 + y^2 = 1, represents a circle in the Cartesian coordinate system.

Key Details:

  • Center of the circle: The center of the circle is at the origin (0,0)(0, 0).
  • Radius of the circle: The radius rr is 1, as the equation is in the standard form of a circle equation (xh)2+(yk)2=r2(x - h)^2 + (y - k)^2 = r^2 where (h,k)(h, k) is the center, and rr is the radius.

This equation describes all the points (x,y)(x, y) that are exactly 1 unit away from the origin.

Would you like more details or have any specific questions about this equation?

Here are five related questions to expand your understanding:

  1. How would the equation change if the circle had a radius of 2?
  2. What would the equation be if the circle were centered at (2,3)(2, 3)?
  3. Can you find the intersection points of this circle with the line y=xy = x?
  4. How would you write the equation of a circle that is tangent to the x-axis?
  5. What is the area of the circle described by the equation x2+y2=1x^2 + y^2 = 1?

Tip: For any equation of a circle, identifying the center and radius helps you quickly understand its geometric properties.

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Math Problem Analysis

Mathematical Concepts

Geometry
Circle Equations

Formulas

Standard form of a circle equation: (x - h)^2 + (y - k)^2 = r^2

Theorems

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Suitable Grade Level

Grades 9-12