Math Problem Statement

Prove the relationship involving second-order partial derivatives for the function z=f(x,y), where x=u^2−v^2 and y=2uv, and show that (∂^2z/∂u^2 + ∂^2z/∂v^2) = 4(∂^2z/∂x^2 + ∂^2z/∂y^2).

Solution

The problem provided involves a function z=f(x,y)z = f(x, y) with variables xx and yy defined in terms of new variables uu and vv. The goal appears to be proving some relationship involving partial derivatives.

From the image:

  1. z=f(x,y)z = f(x, y), where x=u2v2x = u^2 - v^2 and y=2uvy = 2uv.
  2. The task seems to involve proving a relationship related to second-order partial derivatives, possibly involving the Laplacian operator or a similar equation.

The expression to be proved involves second-order partial derivatives of zz with respect to uu and vv: 2zu2+2zv2=4(2zx2+2zy2).\frac{\partial^2 z}{\partial u^2} + \frac{\partial^2 z}{\partial v^2} = 4 \left( \frac{\partial^2 z}{\partial x^2} + \frac{\partial^2 z}{\partial y^2} \right).

This suggests you are tasked with finding and verifying this result by computing the partial derivatives of zz with respect to uu and vv, using the chain rule to express them in terms of the second-order partial derivatives with respect to xx and yy.

Approach

  1. Use the chain rule for multivariable functions to express the partial derivatives of zz with respect to uu and vv in terms of xx and yy.
  2. Compute the second-order partial derivatives with respect to uu and vv.
  3. Compare these with the second-order partial derivatives with respect to xx and yy.
  4. Simplify and prove the equation given in the problem.

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Math Problem Analysis

Mathematical Concepts

Multivariable Calculus
Partial Derivatives
Chain Rule
Second-Order Derivatives

Formulas

(∂^2z/∂u^2 + ∂^2z/∂v^2) = 4(∂^2z/∂x^2 + ∂^2z/∂y^2)
Chain rule for multivariable functions: ∂z/∂u = (∂z/∂x)(∂x/∂u) + (∂z/∂y)(∂y/∂u)

Theorems

Chain Rule
Laplacian Operator

Suitable Grade Level

Undergraduate Mathematics