The given equation is:

$F = \frac{7.35 \times 10^{-18} \times (5 \times 10^{15}) \times (4 \times 10^{9})}{(2.3 \times 10^{-18}) \times (1.7 \times 10^{-18})}$

Step 1: Simplify the numerator

$7.35 \times 5 \times 4 = 7.35 \times 20 = 147$ $10^{-18} \times 10^{15} \times 10^{9} = 10^{-18 + 15 + 9} = 10^{6}$

So, the numerator simplifies to: $147 \times 10^{6}$

Step 2: Simplify the denominator

$2.3 \times 1.7 = 3.91$ $10^{-18} \times 10^{-18} = 10^{-36}$

So, the denominator simplifies to: $3.91 \times 10^{-36}$

Step 3: Divide the simplified terms

$F = \frac{147 \times 10^{6}}{3.91 \times 10^{-36}} = \left(\frac{147}{3.91}\right) \times 10^{6 - (-36)} = \left(\frac{147}{3.91}\right) \times 10^{42}$

$\frac{147}{3.91} \approx 37.6$

Final Answer:

$F \approx 37.6 \times 10^{42} = 3.76 \times 10^{43}$

Would you like me to explain any steps in more detail or help with a related problem?

Here are 5 related questions you might find interesting:

1. How do you multiply and divide numbers in scientific notation?
2. What are the properties of exponents used in this calculation?
3. How do you handle significant figures in scientific notation?
4. Can this formula be applied in physics, such as calculating force?
5. How would the answer change if one of the exponents was negative in the numerator?

Tip: When multiplying or dividing in scientific notation, handle the coefficients and exponents separately for simplicity.