To find out how much money you will have in your savings account after 15 years of depositing $300 monthly with an annual percentage rate (APR) of 3.8%, compounded monthly, you can use the future value of an annuity formula. The formula is:

$FV = P \times \frac{(1 + r)^n - 1}{r}$

where:

• $FV$ is the future value of the investment,
• $P$ is the monthly deposit ($300),
• $r$ is the monthly interest rate (annual rate divided by 12),
• $n$ is the total number of deposits (months).

Given:

• The annual interest rate is 3.8%, so the monthly interest rate $r = \frac{3.8\%}{12} = \frac{0.038}{12} \approx 0.0031667$.
• The number of months $n = 15 \times 12 = 180$.

Plugging in these values into the formula:

$FV = 300 \times \frac{(1 + 0.0031667)^{180} - 1}{0.0031667}$

First, calculate $(1 + 0.0031667)^{180}$:

$(1 + 0.0031667)^{180} \approx 1.84885$

Now, substitute back into the equation:

$FV = 300 \times \frac{1.84885 - 1}{0.0031667}$

$FV = 300 \times \frac{0.84885}{0.0031667}$

$FV = 300 \times 267.97$

$FV \approx 80391$

So, the future value of the savings account after 15 years would be approximately $80,391.