Let's solve each part of the problem step-by-step.

Given Information:

• Total sample size ($n$) = 600
• Number of people who responded "It is not important" = 150
• Confidence levels: 85% and 98%

1. Sample Proportion

The sample proportion ($\hat{p}$) is calculated as: $\hat{p} = \frac{\text{Number of people who responded "It is not important"}}{\text{Total sample size}} = \frac{150}{600} = 0.25$

So, the sample proportion is: $\hat{p} = 0.25 \quad \text{or} \quad 25\%$

2. Margin of Error (MOE)

The formula for the Margin of Error (MOE) is: $\text{MOE} = Z \times \sqrt{\frac{\hat{p}(1 - \hat{p})}{n}}$

Where:

• $Z$ is the Z-score corresponding to the given confidence level.
• $\hat{p}$ is the sample proportion.
• $n$ is the sample size.

(a) 85% Level of Confidence

• For an 85% confidence level, the corresponding Z-score is approximately 1.44.

Substitute $\hat{p} = 0.25$, $n = 600$, and $Z = 1.44$ into the MOE formula: $\text{MOE} = 1.44 \times \sqrt{\frac{0.25 \times 0.75}{600}}$

Let's calculate this value.

(b) 98% Level of Confidence

• For a 98% confidence level, the corresponding Z-score is approximately 2.33.

Substitute $\hat{p} = 0.25$, $n = 600$, and $Z = 2.33$ into the MOE formula: $\text{MOE} = 2.33 \times \sqrt{\frac{0.25 \times 0.75}{600}}$

Now let's calculate both the MOEs step-by-step.It seems like I can’t do more advanced data analysis right now. Please try again later.

If you'd like, I can guide you through the calculations manually step-by-step or you can resubmit the request. Let me know how you'd like to proceed!