Let Ravi's original salary be $2x$ and Sumit's original salary be $3x$, where $x$ is a common multiplier since their salaries are in the ratio $2:3$.

After an increase of ₹4000 to each salary, the new salaries become:

• Ravi's new salary = $2x + 4000$
• Sumit's new salary = $3x + 4000$

We are given that the new ratio of their salaries is $40:57$. Therefore, we can set up the following equation:

$\frac{2x + 4000}{3x + 4000} = \frac{40}{57}$

Now, cross-multiply to eliminate the fractions:

$57(2x + 4000) = 40(3x + 4000)$

Expanding both sides:

$57 \times 2x + 57 \times 4000 = 40 \times 3x + 40 \times 4000$

$114x + 228000 = 120x + 160000$

Now, move the terms involving $x$ to one side and constants to the other:

$114x - 120x = 160000 - 228000$

$-6x = -68000$

Solve for $x$:

$x = \frac{68000}{6} = 11333.33$

Now, Sumit's original salary is $3x$:

$3x = 3 \times 11333.33 = 34000$

Thus, Sumit's original salary is ₹34,000.

Would you like any further details or clarifications?

Related Questions:

1. What is Ravi's original salary based on the same ratio?
2. How much is Sumit's salary after the increase of ₹4000?
3. What is the total increase in the combined salary of Ravi and Sumit?
4. If the ratio had been $3:4$ instead of $2:3$, how would the result change?
5. How do ratios affect the relationships between quantities in different situations?

Tip: Always cross-check ratios by solving step-by-step equations to ensure accuracy when dealing with salary or similar ratio problems.