Math Problem Statement
Solution
Let's delve into the problem step by step. Here's how we tackle it:
(a) Length of the rope:
From the equation , we observe that corresponds to the standing wave function. The wavelength is twice the length of the rope for the second harmonic. Since , the rope's length is:
(b) Speed of the waves:
The angular frequency and the wave number . Wave speed is given by:
(c) Mass of the rope:
The tension , and wave speed relates to the mass per unit length as: The total mass of the rope is:
(d) Period of oscillation for the third harmonic:
For the third harmonic, the frequency , where : The period is the reciprocal of frequency:
Final Answers:
(a) Length of rope:
(b) Speed of waves:
(c) Mass of rope:
(d) Period of oscillation:
Do you want further clarifications on any of these calculations?
Here are some related questions for deeper understanding:
- How is the wave equation derived for a standing wave?
- Why does the second harmonic imply half the wavelength fits the rope's length?
- What are the differences between harmonics in terms of wavelengths and frequencies?
- How does tension affect wave speed?
- What practical applications use these harmonic wave principles?
Tip: Always verify units in equations to ensure physical consistency!
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Math Problem Analysis
Mathematical Concepts
Wave motion
Standing waves
Second harmonic
Wave speed
Mass per unit length
Formulas
Wave speed: v = ω / k
Mass per unit length: μ = T / v²
Fundamental frequency: f = v / (2L)
Period: T = 1 / f
Theorems
Standing wave patterns on strings
Relationship between wave speed, tension, and mass density
Suitable Grade Level
Undergraduate Physics
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