Math Problem Statement

A wooden roller coaster contains a run in the shape of a sinusoidal​ curve, with a series of hills. The crest of each hill is 106 feet above the ground. If it takes a car 1.8 seconds to go from the top of a hill to the bottom ​(6 feet off the​ ground), find a sinusoidal function of the form y equals Upper A sine left parenthesis omega t minus variant phi right parenthesis plus Upper B that models the motion of the coaster train during this run starting at the top of a hill. Question content area bottom Part 1 yequals    enter your response heresine left parenthesis nothing t plus nothing right parenthesis       plus    enter your response here ​(Simplify your answers. Round to the nearest thousandth as​ needed.)

Solution

To find the sinusoidal function that models the motion of the coaster, we need to express it in the form:

y=Asin(ωtϕ)+By = A \sin(\omega t - \phi) + B

Here, yy represents the height of the roller coaster above the ground, AA is the amplitude, ω\omega is the angular frequency, ϕ\phi is the phase shift, BB is the vertical shift, and tt is the time in seconds.

Step 1: Find the amplitude AA

The amplitude AA is the distance from the middle of the sinusoidal curve to the maximum or minimum value. In this case, the maximum height is 106 feet (crest of the hill) and the minimum height is 6 feet (bottom of the hill).

The amplitude is half the distance between the maximum and minimum heights: A=10662=1002=50feetA = \frac{106 - 6}{2} = \frac{100}{2} = 50 \, \text{feet}

Step 2: Find the vertical shift BB

The vertical shift BB is the midpoint between the maximum and minimum heights: B=106+62=1122=56feetB = \frac{106 + 6}{2} = \frac{112}{2} = 56 \, \text{feet}

Step 3: Find the angular frequency ω\omega

It takes 1.8 seconds to go from the top of a hill to the bottom, which is half the period. The total period TT is the time it takes to go from one crest (top of the hill) to the next crest (or one full cycle). Therefore: T=2×1.8=3.6secondsT = 2 \times 1.8 = 3.6 \, \text{seconds}

The angular frequency ω\omega is related to the period by the formula: ω=2πT=2π3.61.745radians per second\omega = \frac{2\pi}{T} = \frac{2\pi}{3.6} \approx 1.745 \, \text{radians per second}

Step 4: Find the phase shift ϕ\phi

Since the coaster starts at the top of the hill at t=0t = 0, the sine function should have a phase shift to account for the fact that sine normally starts at 0. A cosine function would start at the maximum, but using sine, we need to account for the fact that we start at a crest, meaning a phase shift of π2\frac{\pi}{2}.

Thus, ϕ=π2\phi = -\frac{\pi}{2}.

Step 5: Write the final equation

Now, we can plug in the values for AA, ω\omega, ϕ\phi, and BB into the sinusoidal equation:

y=50sin(1.745tπ2)+56y = 50 \sin\left(1.745 t - \frac{\pi}{2}\right) + 56

This is the sinusoidal function that models the motion of the roller coaster during the run.

Do you have any questions or would you like further details?

Here are 5 related questions:

  1. How would the equation change if the coaster started at the bottom of the hill?
  2. What would happen to the function if the amplitude were doubled?
  3. How does changing the period of the motion affect the angular frequency?
  4. Can the phase shift ϕ\phi be in degrees instead of radians?
  5. How would this equation model the coaster if the ground level was shifted?

Tip: When solving sinusoidal problems, always ensure the correct identification of amplitude, vertical shift, and period, as these control the height and timing of the wave.

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Math Problem Analysis

Mathematical Concepts

Trigonometry
Sinusoidal Functions
Amplitude
Period
Phase Shift
Vertical Shift

Formulas

y = A sin(ωt - ϕ) + B
Amplitude: A = (max height - min height) / 2
Vertical Shift: B = (max height + min height) / 2
Angular Frequency: ω = 2π / Period
Phase Shift: ϕ = -π / 2

Theorems

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Suitable Grade Level

Grades 10-12