Math Problem Statement

Solve for x in a right triangle where the hypotenuse is 62 units and one leg is 41 units.

Solution

To solve the problem, we need to find the length of side xx in the right triangle using the Pythagorean theorem. The Pythagorean theorem states that in a right triangle, the square of the length of the hypotenuse (cc) is equal to the sum of the squares of the lengths of the other two sides (aa and bb):

c2=a2+b2c^2 = a^2 + b^2

In the triangle provided:

  • The hypotenuse c=62c = 62
  • One leg a=41a = 41
  • The other leg b=xb = x

We need to solve for xx:

622=412+x262^2 = 41^2 + x^2

Calculating the squares:

3844=1681+x23844 = 1681 + x^2

Subtract 1681 from both sides to isolate x2x^2:

38441681=x23844 - 1681 = x^2

2163=x22163 = x^2

Now, take the square root of both sides:

x=2163x = \sqrt{2163}

Calculating the square root:

x46.5x \approx 46.5

So, the length of xx is approximately 46.546.5.

Would you like further details or have any questions about this solution?

Here are some related questions to consider:

  1. How does the Pythagorean theorem apply to non-right triangles?
  2. Can you find the length of the hypotenuse if both legs are known?
  3. What are some real-life applications of the Pythagorean theorem?
  4. How does trigonometry relate to the Pythagorean theorem?
  5. What happens to the formula if the triangle sides are not integers?

Tip: The Pythagorean theorem only applies to right-angled triangles, so always verify the angle before applying it.

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Math Problem Analysis

Mathematical Concepts

Geometry
Right Triangles
Pythagorean Theorem

Formulas

c^2 = a^2 + b^2

Theorems

Pythagorean Theorem

Suitable Grade Level

Grades 8-10