It seems like you've uploaded an image with a geometry problem. Let me break it down for you:

The problem is based on a right triangle $ABC$, where $AB < AC$, and the altitude from vertex $A$ to side $BC$ is $AD$. There is a point $E$ on segment $DC$ such that $DB = DE$. The problem has two parts:

Part (a):

Prove that triangle $ABE$ is an isosceles triangle.

Part (b):

From point $E$, draw line $EF$ perpendicular to $AC$ with point $F$ on line $AC$ (and $F$ lies on segment $AC$). Then, from point $C$, draw a perpendicular line $CK$ to line $AE$, and prove that lines $AD$, $EF$, and $CK$ are concurrent (i.e., meet at the same point).

Would you like a more detailed breakdown or a step-by-step solution to either of these parts?