Math Problem Statement

Write the given expression in the form k sin(x + α) for 0 ≤ α < 2π. Round α to 3 decimal places. Do not round any intermediate calculations. Express −15 sin(x) + 8 cos(x) in the desired form.

Solution

We are asked to express 15sinx+8cosx-15\sin{x} + 8\cos{x} in the form ksin(x+α)k\sin(x + \alpha), where 0α<2π0 \leq \alpha < 2\pi. This transformation is based on the idea of combining sine and cosine terms into a single sinusoidal expression. Here's how we can proceed:

Step-by-Step Process:

  1. Expression to Match: We are trying to match the given expression 15sinx+8cosx-15\sin{x} + 8\cos{x} to the form: ksin(x+α)=k(sinxcosα+cosxsinα).k\sin(x + \alpha) = k(\sin{x}\cos{\alpha} + \cos{x}\sin{\alpha}). Expanding the right-hand side: k(sinxcosα+cosxsinα)=kcosαsinx+ksinαcosx.k(\sin{x}\cos{\alpha} + \cos{x}\sin{\alpha}) = k\cos{\alpha}\sin{x} + k\sin{\alpha}\cos{x}.

  2. Coefficient Matching: From this, we equate the coefficients of sinx\sin{x} and cosx\cos{x} in both expressions: -15 = k\cos{\alpha} \quad \text{(for the \sin{x} term)}, 8 = k\sin{\alpha} \quad \text{(for the \cos{x} term)}.

  3. Find kk: The amplitude kk is given by: k=(15)2+82=225+64=289=17.k = \sqrt{(-15)^2 + 8^2} = \sqrt{225 + 64} = \sqrt{289} = 17.

  4. Find α\alpha: To find α\alpha, use the relationships: cosα=1517,sinα=817.\cos{\alpha} = \frac{-15}{17}, \quad \sin{\alpha} = \frac{8}{17}. Now, compute α\alpha using the arctangent function: α=tan1(815).\alpha = \tan^{-1}\left(\frac{8}{-15}\right). The angle α\alpha is in the second quadrant because cosα\cos{\alpha} is negative and sinα\sin{\alpha} is positive.

    α=tan1(815)tan1(0.5333).\alpha = \tan^{-1}\left(\frac{8}{-15}\right) \approx \tan^{-1}(-0.5333). Using a calculator, α2.654\alpha \approx 2.654 radians (to 3 decimal places).

Final Answer:

The given expression 15sinx+8cosx-15\sin{x} + 8\cos{x} can be written as: 17sin(x+2.654).17\sin(x + 2.654).

Let me know if you'd like further details or clarifications!

Related Questions:

  1. How is the amplitude kk derived from the coefficients of sinx\sin{x} and cosx\cos{x}?
  2. Why does the angle α\alpha end up in the second quadrant?
  3. Can we use a different method to express 15sinx+8cosx-15\sin{x} + 8\cos{x}?
  4. How can we verify that the expression 17sin(x+2.654)17\sin(x + 2.654) is equivalent to the original one?
  5. What would the expression look like if we used cosine instead of sine?

Tip:

To remember which quadrant an angle lies in when using inverse trigonometric functions, pay attention to the signs of sine and cosine!

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Math Problem Analysis

Mathematical Concepts

Trigonometry
Amplitude and Phase Shift
Sine and Cosine Transformation

Formulas

k = √(a^2 + b^2) for amplitude
α = tan⁻¹(b/a) for phase shift
k sin(x + α) = k(sin(x)cos(α) + cos(x)sin(α))

Theorems

Pythagorean identity

Suitable Grade Level

Grades 10-12