Math Problem Statement
Solution
We are asked to express in the form , where . This transformation is based on the idea of combining sine and cosine terms into a single sinusoidal expression. Here's how we can proceed:
Step-by-Step Process:
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Expression to Match: We are trying to match the given expression to the form: Expanding the right-hand side:
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Coefficient Matching: From this, we equate the coefficients of and in both expressions: -15 = k\cos{\alpha} \quad \text{(for the \sin{x} term)}, 8 = k\sin{\alpha} \quad \text{(for the \cos{x} term)}.
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Find : The amplitude is given by:
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Find : To find , use the relationships: Now, compute using the arctangent function: The angle is in the second quadrant because is negative and is positive.
Using a calculator, radians (to 3 decimal places).
Final Answer:
The given expression can be written as:
Let me know if you'd like further details or clarifications!
Related Questions:
- How is the amplitude derived from the coefficients of and ?
- Why does the angle end up in the second quadrant?
- Can we use a different method to express ?
- How can we verify that the expression is equivalent to the original one?
- What would the expression look like if we used cosine instead of sine?
Tip:
To remember which quadrant an angle lies in when using inverse trigonometric functions, pay attention to the signs of sine and cosine!
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Math Problem Analysis
Mathematical Concepts
Trigonometry
Amplitude and Phase Shift
Sine and Cosine Transformation
Formulas
k = √(a^2 + b^2) for amplitude
α = tan⁻¹(b/a) for phase shift
k sin(x + α) = k(sin(x)cos(α) + cos(x)sin(α))
Theorems
Pythagorean identity
Suitable Grade Level
Grades 10-12