Math Problem Statement

Rewrite each quadratic equation in standard form, then identify the values of a, b, and c.

Solution

The image shows a set of quadratic equations where you are tasked with writing each equation in standard form and then identifying the values of aa, bb, and cc. I will help you with each one step by step.

Standard form of a quadratic equation:

The standard form of a quadratic equation is: ax2+bx+c=0ax^2 + bx + c = 0 where:

  • aa is the coefficient of x2x^2,
  • bb is the coefficient of xx,
  • cc is the constant term.

Let's work through the equations one by one.

1. 6(x1.1)(2x3)=46(x - 1.1)(2x - 3) = -4

First, expand and simplify the equation: 6(x1.1)(2x3)=46(x - 1.1)(2x - 3) = -4 Step 1: Multiply the two binomials: (x1.1)(2x3)=x(2x3)1.1(2x3)=2x23x2.2x+3.3=2x25.2x+3.3(x - 1.1)(2x - 3) = x(2x - 3) - 1.1(2x - 3) = 2x^2 - 3x - 2.2x + 3.3 = 2x^2 - 5.2x + 3.3 Step 2: Multiply by 6: 6(2x25.2x+3.3)=12x231.2x+19.86(2x^2 - 5.2x + 3.3) = 12x^2 - 31.2x + 19.8 Step 3: Set the equation equal to 0: 12x231.2x+19.8+4=012x231.2x+23.8=012x^2 - 31.2x + 19.8 + 4 = 0 \quad \Rightarrow \quad 12x^2 - 31.2x + 23.8 = 0 Thus, the equation is in standard form: 12x231.2x+23.8=012x^2 - 31.2x + 23.8 = 0.

  • a=12a = 12
  • b=31.2b = -31.2
  • c=23.8c = 23.8

2. 4k21=7k4k^2 - 1 = -7k

Rearrange the terms to get everything on one side of the equation: 4k21+7k=04k2+7k1=04k^2 - 1 + 7k = 0 \quad \Rightarrow \quad 4k^2 + 7k - 1 = 0 Thus, the equation is in standard form: 4k2+7k1=04k^2 + 7k - 1 = 0.

  • a=4a = 4
  • b=7b = 7
  • c=1c = -1

3. 17j2=4917j^2 = 49

Rearrange the terms to get the equation equal to 0: 17j249=017j^2 - 49 = 0 Thus, the equation is in standard form: 17j249=017j^2 - 49 = 0.

  • a=17a = 17
  • b=0b = 0 (since there is no jj-term)
  • c=49c = -49

4. 3m2+7m=43m^2 + 7m = 4

Rearrange the terms to get the equation equal to 0: 3m2+7m4=03m^2 + 7m - 4 = 0 Thus, the equation is in standard form: 3m2+7m4=03m^2 + 7m - 4 = 0.

  • a=3a = 3
  • b=7b = 7
  • c=4c = -4

5. x2=2x+10x^2 = 2x + 10

Rearrange the terms to get the equation equal to 0: x22x10=0x^2 - 2x - 10 = 0 Thus, the equation is in standard form: x22x10=0x^2 - 2x - 10 = 0.

  • a=1a = 1
  • b=2b = -2
  • c=10c = -10

Do you want more details or have any further questions?

Here are 5 questions to expand your understanding:

  1. How can you solve these quadratic equations once they are in standard form?
  2. Can you explain how to find the roots of a quadratic equation using the quadratic formula?
  3. What does the discriminant (b24acb^2 - 4ac) tell us about the nature of the solutions?
  4. What other methods can be used to solve quadratic equations apart from factoring and the quadratic formula?
  5. How would you graph these quadratic functions and determine their key features?

Tip: Always ensure to have the equation in standard form before identifying aa, bb, and cc. This makes further steps like solving or graphing much easier.

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Math Problem Analysis

Mathematical Concepts

Quadratic Equations
Algebra

Formulas

Standard form of quadratic equation ax^2 + bx + c = 0

Theorems

Expansion of binomials
Quadratic formula

Suitable Grade Level

Grades 8-10