Math Problem Statement

Find an equivalent integral for the given double integrals with the order of integration reversed: \( \int_{-1}^3 \int_{y^2+2}^{2y+5} f(x, y) dx \, dy \)

Solution

To solve this problem, we need to reverse the order of integration for the given double integral:

13y2+22y+5f(x,y)dxdy\int_{-1}^{3} \int_{y^2 + 2}^{2y + 5} f(x, y) \, dx \, dy

Step 1: Understand the region of integration

The original limits of integration are:

  • For yy: 1y3-1 \leq y \leq 3
  • For xx: y2+2x2y+5y^2 + 2 \leq x \leq 2y + 5

This represents a region in the xyxy-plane where xx varies between y2+2y^2 + 2 and 2y+52y + 5, and yy varies between 1-1 and 33. To reverse the order of integration, we need to:

  1. Identify the region of integration in the xyxy-plane.
  2. Express this region with xx as the outer integral and yy as the inner integral.

Step 2: Analyze the boundary curves

The bounds for xx are given by: x=y2+2(parabolic curve)x = y^2 + 2 \quad \text{(parabolic curve)} x=2y+5(linear curve)x = 2y + 5 \quad \text{(linear curve)}

We also know that yy ranges from 1-1 to 33.

To find the points of intersection between these two curves, solve: y2+2=2y+5y^2 + 2 = 2y + 5 Simplify: y22y3=0y^2 - 2y - 3 = 0 Factorize: (y3)(y+1)=0(y - 3)(y + 1) = 0 Thus, the points of intersection are y=1y = -1 and y=3y = 3.

So, the region of integration is bounded by:

  1. x=y2+2x = y^2 + 2 (below the curve).
  2. x=2y+5x = 2y + 5 (above the curve).
  3. From y=1y = -1 to y=3y = 3.

Step 3: Reverse the order of integration

Now, we switch the order of integration, where xx becomes the outer integral. The new limits are:

  • For xx: The minimum value of xx is at y2+2y^2 + 2 when y=1y = -1, which is x=(1)2+2=3x = (-1)^2 + 2 = 3. The maximum value of xx is at 2y+52y + 5 when y=3y = 3, which is x=2(3)+5=11x = 2(3) + 5 = 11. So, xx varies from 33 to 1111.
  • For yy: For a fixed xx, yy varies between the curves x=y2+2x = y^2 + 2 and x=2y+5x = 2y + 5. Solving for yy:
    • From x=y2+2x = y^2 + 2: y=±x2y = \pm\sqrt{x - 2}
    • From x=2y+5x = 2y + 5: y=x52y = \frac{x - 5}{2}

Thus, the new integral becomes: 311x2x52f(x,y)dydx\int_{3}^{11} \int_{\sqrt{x-2}}^{\frac{x-5}{2}} f(x, y) \, dy \, dx

Final Answer:

The equivalent integral with the order of integration reversed is: 311x2x52f(x,y)dydx\int_{3}^{11} \int_{\sqrt{x-2}}^{\frac{x-5}{2}} f(x, y) \, dy \, dx


Would you like a detailed explanation of any step, or clarification on the bounds?

5 Related Questions:

  1. How do you determine the intersection points of curves in general?
  2. What are the general steps to reverse the order of integration in double integrals?
  3. Why is it important to carefully analyze the region of integration when reversing limits?
  4. How do parabolic and linear boundaries affect the integration setup?
  5. Can this process be extended to triple integrals?

Tip:

When reversing the order of integration, always sketch the region to avoid mistakes with the bounds!

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Math Problem Analysis

Mathematical Concepts

Double Integrals
Reversing Order of Integration
Analyzing Regions of Integration

Formulas

Intersection points: Solve \(y^2 + 2 = 2y + 5\)
Integration bounds setup

Theorems

Concept of double integration in rectangular regions

Suitable Grade Level

Grades 11-12 or College Level