Math Problem Statement
There are 3 vectors in a 2D coordinate with unit vector π₯Μ and π¦Μ along x and y axes respectively. The magnitude of πβ is 5 and it forms an angle of 60π with the positive x-axis. Vector πββ = 5π₯Μ + 8π¦Μ. The coordinates of the starting and ending points of πβ are (4, 5) and (12, 7). Calculate the resultant of πβ + πββ + πβ
Solution
We are asked to calculate the resultant of three vectors , where:
- Vector has a magnitude of 5 and forms an angle of with the positive x-axis.
- Vector .
- Vector has starting and ending points at (4, 5) and (12, 7), respectively.
Step 1: Express each vector in component form
Vector
The components of can be derived using trigonometry:
- The x-component is .
- The y-component is .
Since and , we get: Thus, .
Vector
This vector is already given in component form:
Vector
To find the components of , we calculate the differences between the ending and starting points: Thus, .
Step 2: Add the vectors
Now, sum the components of , , and in the x- and y-directions separately.
x-component:
y-component:
Step 3: Calculate the magnitude of the resultant vector
The magnitude of the resultant vector is given by the Pythagorean theorem:
Let's compute that.
The magnitude of the resultant vector is approximately 21.11.
Would you like more details on any part of the calculation? Here are some questions to consider:
- How can the direction of the resultant vector be determined?
- What are unit vectors and how do they affect vector addition?
- How would the result change if the angle for were different?
- How can you represent the vectors graphically?
- What would the calculation look like in 3D?
Tip: Always ensure the angles used in vector calculations are in the correct unit (degrees or radians).
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Math Problem Analysis
Mathematical Concepts
Vector addition
Trigonometry
Pythagorean theorem
Coordinate geometry
Formulas
Vector components: a_x = magnitude * cos(angle), a_y = magnitude * sin(angle)
Resultant vector magnitude: |R| = β(R_x^2 + R_y^2)
Theorems
Pythagorean theorem
Suitable Grade Level
Grades 10-12
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