Math Problem Statement

A luggage wagon is being pulled with vector force V, which has a magnitude of 900 pounds at an angle of elevation of 67 degrees. Resolve the vector V into components. The horizontal component is _____ (Round to the nearest integer).

Solution

To resolve the vector VV of 900 pounds at an angle of 67 degrees into its horizontal and vertical components, we can use trigonometric functions:

Given:

  • V=900V = 900 pounds
  • Angle θ=67\theta = 67^\circ

Horizontal Component

The horizontal component VxV_x can be found using: Vx=Vcos(θ)V_x = V \cdot \cos(\theta) Substitute the values: Vx=900cos(67)V_x = 900 \cdot \cos(67^\circ)

Using the cosine of 67 degrees (approximately 0.3907): Vx=9000.3907352V_x = 900 \cdot 0.3907 \approx 352

So, the horizontal component, rounded to the nearest integer, is 352 pounds.

Would you like details on the vertical component or have any questions?


Related Questions

  1. How do we calculate the vertical component of a vector?
  2. What is the significance of resolving vectors into components?
  3. How does changing the angle affect the horizontal and vertical components?
  4. How can vectors be used in physics problems involving forces?
  5. What are some real-world applications of vector decomposition?

Tip

When resolving vectors, remember that the horizontal component uses cosine, and the vertical component uses sine of the angle with the horizontal.

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Math Problem Analysis

Mathematical Concepts

Vector Decomposition
Trigonometry

Formulas

Horizontal component: V_x = V * cos(θ)
Vertical component: V_y = V * sin(θ)

Theorems

Trigonometric Functions for Right Triangles

Suitable Grade Level

Grades 10-12