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To resolve the vector \( V \) of 900 pounds at an angle of 67 degrees into its horizontal and vertical components, we can use trigonometric functions:

Given:
- \( V = 900 \) pounds
- Angle \( \theta = 67^\circ \)

### Horizontal Component
The horizontal component \( V_x \) can be found using:
\[
V_x = V \cdot \cos(\theta)
\]
Substitute the values:
\[
V_x = 900 \cdot \cos(67^\circ)
\]

Using the cosine of 67 degrees (approximately 0.3907):
\[
V_x = 900 \cdot 0.3907 \approx 352
\]

So, the horizontal component, rounded to the nearest integer, is **352 pounds**.

Would you like details on the vertical component or have any questions?

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### Related Questions
1. How do we calculate the vertical component of a vector?
2. What is the significance of resolving vectors into components?
3. How does changing the angle affect the horizontal and vertical components?
4. How can vectors be used in physics problems involving forces?
5. What are some real-world applications of vector decomposition?

### Tip
When resolving vectors, remember that the horizontal component uses cosine, and the vertical component uses sine of the angle with the horizontal.

A luggage wagon is being pulled with vector force V, which has a magnitude of 900 pounds at an angle of elevation of 67 degrees. Resolve the vector V into components. The horizontal component is _____ (Round to the nearest integer).

Learn how to resolve a vector force of 900 pounds at a 67-degree angle into horizontal and vertical components. This example demonstrates key trigonometric concepts and is suitable for high school students. Includes step-by-step calculations and rounding tips.

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