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The expression you've provided is:

\[
\frac{x+2}{(x-1)(x^2+2)}
\]

To resolve this into partial fractions, we need to express the fraction as a sum of simpler fractions. The general form for this decomposition is:

\[
\frac{x+2}{(x-1)(x^2+2)} = \frac{A}{x-1} + \frac{Bx + C}{x^2+2}
\]

Here’s how to proceed:

1. **Multiply both sides by the denominator** \((x-1)(x^2+2)\) to eliminate the denominators:

   \[
   x + 2 = A(x^2 + 2) + (Bx + C)(x-1)
   \]

2. **Expand the right-hand side:**

   \[
   x + 2 = A(x^2 + 2) + (Bx + C)(x - 1)
   \]
   \[
   = Ax^2 + 2A + Bx^2 - Bx + Cx - C
   \]
   \[
   = (A + B)x^2 + (-B + C)x + (2A - C)
   \]

3. **Now, equate the coefficients of corresponding powers of \(x\) from both sides of the equation:**

   For \(x^2\): \( A + B = 0 \)

   For \(x^1\): \( -B + C = 1 \)

   For the constant term: \( 2A - C = 2 \)

4. **Solve the system of equations:**

   - From \( A + B = 0 \), we have \( B = -A \).
   - Substitute \( B = -A \) into \( -B + C = 1 \), giving \( A + C = 1 \), so \( C = 1 - A \).
   - Substitute \( C = 1 - A \) into \( 2A - C = 2 \), giving:
     \[
     2A - (1 - A) = 2 \Rightarrow 3A - 1 = 2 \Rightarrow 3A = 3 \Rightarrow A = 1
     \]

   - Since \( A = 1 \), \( B = -1 \), and \( C = 1 - A = 0 \).

5. **Substitute back into the partial fraction form:**

   \[
   \frac{x+2}{(x-1)(x^2+2)} = \frac{1}{x-1} + \frac{-x}{x^2+2}
   \]

   This can be written as:

   \[
   \frac{x+2}{(x-1)(x^2+2)} = \frac{1}{x-1} - \frac{x}{x^2+2}
   \]

This is the partial fraction decomposition of the given expression.

Would you like any further details or have any questions?

Here are some related questions you might find interesting:

1. How would you perform partial fraction decomposition if the denominator had repeated linear factors?
2. What happens if the numerator's degree is higher than the denominator's?
3. How can partial fractions be used in the integration of rational functions?
4. What is the role of complex roots in partial fraction decomposition?
5. Can you decompose a fraction if the denominator is already a sum of irreducible quadratic terms?

**Tip:** When decomposing fractions, always check the degree of the numerator and denominator. If the degree of the numerator is equal to or greater than the denominator, you'll need to perform polynomial division first.

Learn how to resolve the expression (x+2)/((x-1)(x^2+2)) into partial fractions with a detailed step-by-step solution. This problem covers key algebraic concepts, including partial fraction decomposition. Suitable for advanced high school students.

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