Math Problem Statement

Jim has scored 78, 92, 75, and 65 on his previous four tests. What score does he need on his next test so that his average (mean) is 77?

Solution

To solve this problem, let's follow these steps:

  1. Define the Variables: Let xx be the score Jim needs on his next test to achieve an average of 77.

  2. Set up the Equation for the Average: Jim has already taken four tests with scores of 78, 92, 75, and 65. The average score for five tests (including his next score xx) should be 77.

    The formula for the average is: Average=Sum of all scoresNumber of scores\text{Average} = \frac{\text{Sum of all scores}}{\text{Number of scores}}

  3. Plug in the Values: 77=78+92+75+65+x577 = \frac{78 + 92 + 75 + 65 + x}{5}

  4. Simplify the Equation:

    • First, add up the scores from the first four tests: 78+92+75+65=31078 + 92 + 75 + 65 = 310
    • Substitute this back into the equation: 77=310+x577 = \frac{310 + x}{5}
  5. Solve for xx:

    • Multiply both sides by 5 to eliminate the denominator: 77×5=310+x77 \times 5 = 310 + x
    • This simplifies to: 385=310+x385 = 310 + x
    • Subtract 310 from both sides: x=75x = 75

Answer

Jim needs a score of 75 on his next test to achieve an average of 77.

Would you like further clarification on this problem, or do you have any additional questions?

Here are some related questions that expand on this concept:

  1. How would the score Jim needs change if he wanted an average of 80 instead?
  2. What would Jim’s average be if he scored 85 on his next test?
  3. If Jim's scores had a different set of values, how would the approach to find the required score change?
  4. How would you calculate the required score if Jim had already taken five tests instead of four?
  5. What happens to the average if we increase the number of tests but keep a target mean?

Tip: When calculating averages, multiplying both sides of the equation by the number of items can simplify finding a missing value.

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Math Problem Analysis

Mathematical Concepts

Algebra
Mean (Average)
Linear Equation

Formulas

Mean (Average) = (Sum of all scores) / (Number of scores)

Theorems

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Suitable Grade Level

Grades 6-8