Math Problem Statement

Annual demand for a product is 16,120 units; weekly demand is 310 units with a standard deviation of 65 units. The cost of placing an order is $155, and the time from ordering to receipt is four weeks. The annual inventory carrying cost is $0.65 per unit.

a. To provide a 90 percent service probability, what must the reorder point be? (Use Excel's NORMSINV() function to find the correct critical value for the given α-level. Do not round intermediate calculations. Round "z" value to 2 decimal places and final answer to the nearest whole number.)

b. Suppose the production manager is told to reduce the safety stock of this item by 75 units. If this is done, what will the new service probability be? (Use Excel's NORMSDIST() function to find the correct probability for your computed Z-value. Round your answer to the nearest whole number.)

Solution

Let’s break the problem into two parts: part (a) is about finding the reorder point, and part (b) involves calculating the new service probability after reducing the safety stock.

Part (a) – Reorder Point Calculation

The reorder point (ROP) is the point at which a new order should be placed to avoid running out of stock. It is calculated using the formula:

ROP=dL+ZσL\text{ROP} = d \cdot L + Z \cdot \sigma_L

Where:

  • dd = average weekly demand = 310 units
  • LL = lead time in weeks = 4 weeks
  • ZZ = z-value corresponding to the desired service probability (90%)
  • σL\sigma_L = standard deviation of demand during lead time = σL\sigma \cdot \sqrt{L}

Steps:

  1. Calculate the standard deviation of demand during lead time (σL\sigma_L): σL=654=652=130\sigma_L = 65 \cdot \sqrt{4} = 65 \cdot 2 = 130

  2. Find the Z-value for a 90% service level using Excel's NORMSINV(0.90). From tables or using Excel: Z=1.28Z = 1.28

  3. Calculate the reorder point (ROP): ROP=(3104)+(1.28130)\text{ROP} = (310 \cdot 4) + (1.28 \cdot 130) ROP=1240+166.4=1406.4\text{ROP} = 1240 + 166.4 = 1406.4 Rounded to the nearest whole number: ROP=1406\text{ROP} = 1406

Part (b) – New Service Probability

The safety stock is calculated as:

Safety Stock=ZσL\text{Safety Stock} = Z \cdot \sigma_L From part (a), the initial safety stock was:

Safety Stock=1.28130=166.4\text{Safety Stock} = 1.28 \cdot 130 = 166.4

If the safety stock is reduced by 75 units, the new safety stock will be:

New Safety Stock=166.475=91.4\text{New Safety Stock} = 166.4 - 75 = 91.4

Now, calculate the new ZZ-value corresponding to this new safety stock:

Znew=91.4130=0.703Z_{\text{new}} = \frac{91.4}{130} = 0.703

Use Excel's NORMSDIST(0.703) to find the new service probability. This gives:

New Service Probability=0.758\text{New Service Probability} = 0.758

So, the new service probability is approximately 75.8%, or rounded to the nearest whole number:

New Service Probability=76%\text{New Service Probability} = 76\%

Summary of Results:

  • (a) The reorder point for a 90% service probability is 1406 units.
  • (b) After reducing the safety stock by 75 units, the new service probability is approximately 76%.

Would you like a detailed breakdown of any part of the solution?

Here are 5 related questions you might be interested in:

  1. How does changing the lead time affect the reorder point?
  2. What happens to the reorder point if the demand variability increases?
  3. How is safety stock calculated for different service levels?
  4. What role does carrying cost play in inventory management decisions?
  5. How do changes in ordering costs impact the economic order quantity (EOQ)?

Tip: Always adjust safety stock based on both demand variability and desired service levels to balance inventory costs effectively.

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Math Problem Analysis

Mathematical Concepts

Inventory Management
Service Level
Reorder Point
Safety Stock
Probability

Formulas

Reorder Point (ROP) = d * L + Z * σ_L
σ_L = σ * √L
Safety Stock = Z * σ_L
Z-value = NORMSINV(service probability)
New service probability = NORMSDIST(new Z-value)

Theorems

Normal Distribution
Z-score Calculation

Suitable Grade Level

Undergraduate Business or Operations Management