Let's solve the problems visible in the image:

Problem 1 (Top Left):

Trapezoid QRST with vertices $Q(4, -1), R(6, -1), S(8, -6), T(2, -6)$ is reflected over the line $x = -1$. What is the location of $T'$?

To reflect a point across the vertical line $x = -1$, the formula is: $x' = 2(-1) - x$ For point $T(2, -6)$:

• Apply the formula to the $x$-coordinate: $x' = 2(-1) - 2 = -2 - 2 = -4$
• The $y$-coordinate remains the same.

Thus, $T'( -4, -6 )$.

Problem 2 (Top Right):

Parallelogram STUV with vertices $S(-3, 4), T(-1, 7), U(5, 7), V(3, 4)$ is reflected over the line $y = -x$. What is the location of $T'$?

When reflecting a point