The question asks how to reflect the function $f(x) = \frac{2}{3}x - 9$ over the y-axis.

When a function is reflected over the y-axis, we replace $x$ with $-x$ in the function. So, let's reflect the function step by step:

1. Start with the original function: $f(x) = \frac{2}{3}x - 9$

2. To reflect over the y-axis, replace $x$ with $-x$: $g(x) = \frac{2}{3}(-x) - 9$

3. Simplify: $g(x) = -\frac{2}{3}x - 9$

Thus, the reflected function is: $g(x) = -\frac{2}{3}x - 9$

This corresponds to the third option in your quiz: g(x) = -$\frac{2}{3}x - 9$.

Let me know if you want any further details!

Here are five follow-up questions related to this concept:

1. How does reflecting a function over the x-axis differ from reflecting over the y-axis?
2. What happens to the slope when a linear function is reflected over the y-axis?
3. If $f(x) = ax + b$, what will the reflected function over the y-axis be in general terms?
4. How would you reflect a quadratic function over the y-axis?
5. Can a function remain unchanged when reflected over the y-axis? If so, what type of function?

Tip: To reflect a function over the y-axis, simply replace $x$ with $-x$ in the function equation!