what is the reduce row echeleon form of 1 −2 8 −1 −1 −5 −7 | 0 0 0 1 −7 0 7 | 0 0 0 0 0 1 9 | sorry its 3x6

No problem! You mentioned that the matrix is a \(3 \times 6\) matrix, which means it has 3 rows and 6 columns. The matrix you provided seems to be split into different parts, so let's arrange it properly in a standard matrix form:

\[
\begin{bmatrix}
1 & -2 & 8 & -1 & -1 & -5 \\
-7 & 0 & 0 & 0 & 1 & -7 \\
0 & 0 & 0 & 0 & 1 & 9
\end{bmatrix}
\]

Now, let's find the reduced row echelon form (RREF) of this matrix. To do this, we'll use Gaussian elimination, applying a series of row operations to achieve the RREF.

### Steps to Achieve RREF
1. **Identify the leading entry (pivot) in each row.**
2. **Make the leading entry 1 if it is not already.**
3. **Use row operations to create zeros in all positions above and below each pivot.**

Let's calculate this.

what is the reduce row echelon form of 1 −2 8 −1 −1 −5 −7 | 0 0 0 1 −7 0 7 | 0 0 0 0 0 1 9 | sorry its 3x6

This solution demonstrates how to find the reduced row echelon form (RREF) of a 3x6 matrix using Gaussian elimination. Explore key concepts in linear algebra such as matrix row operations and RREF. Suitable for advanced high school or undergraduate students.

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