Math Problem Statement
Solution
The image shows a mathematical sequence problem that reads:
"1. A sequence has and satisfies
for all positive integers . For which values of are all the terms of the sequence still integers?"
Solution
To determine for which values of all the terms of the sequence are integers, we start by calculating the first few terms:
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For : So, , which is an integer.
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For : So, , which is an integer.
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For : So, , which is an integer.
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For : So, , which is an integer.
The pattern suggests that each term is an integer. To generalize, we can observe that if is an integer, is computed by multiplying and , which is always even, and then dividing by 2, thus remains an integer.
Conclusion:
Given the recursive formula, all terms will be integers for every positive integer . This is because the sequence starts with an integer, and each subsequent term is derived from multiplying an integer with another integer and dividing by 2, which consistently yields an integer.
Would you like more details on this solution or have any further questions?
Follow-up Questions:
- How would the sequence change if were a different integer?
- Can you derive a general formula for based on the recursive relation?
- How does the behavior of this sequence compare to a geometric or arithmetic sequence?
- What are some real-life applications of such recursive sequences?
- How does the property of being an integer for all relate to other types of sequences?
Tip:
When working with recursive sequences, calculating the first few terms often helps in identifying patterns and understanding the general behavior of the sequence.
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Math Problem Analysis
Mathematical Concepts
Sequences
Recursive Sequences
Number Theory
Formulas
an+1 = (an(an + 1))/2
Theorems
Basic properties of integers
Induction (for generalized proof)
Suitable Grade Level
Grades 10-12
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