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The question asks for the width of a rectangle, given that the area is 63 square meters and the length is 9 meters.

We know that the area \( A \) of a rectangle is given by the formula:

\[
A = \text{length} \times \text{width}
\]

Substituting the known values:

\[
63 = 9 \times \text{width}
\]

To solve for the width, divide both sides by 9:

\[
\text{width} = \frac{63}{9} = 7 \, \text{meters}
\]

Thus, the correct answer is \( \boxed{7} \), which corresponds to option A.

Would you like further details or have any questions?

Here are five relative questions to expand on this:

1. How do you calculate the perimeter of a rectangle?
2. What is the area formula for a triangle, and how does it differ from that of a rectangle?
3. If the width were doubled, what would the new area be?
4. What are the units of area, and why are they squared?
5. How can you calculate the diagonal of a rectangle using the Pythagorean theorem?

**Tip:** Always double-check units when working with area or volume, as they can change based on the type of measurement (e.g., meters vs. square meters).

A rectangle has an area of 63 square meters and a length of 9 meters. What is the width, in meters, of the rectangle?

This problem asks you to find the width of a rectangle when given the area and length. The area of the rectangle is 63 square meters and the length is 9 meters. Using the formula for the area of a rectangle, solve for the width. Suitable for students in Grades 5-7.

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