Math Problem Statement

Sapling of Gulmohar are planted on the boundary at a distance of 1 m from each other. There is a rectangular grassy lawn in the plot as shown in the figure. The students are sowing seeds of flowering plants on the remaining area of the plot. (a) Find the width of rectangle PQRS. (b) Find the distance between the vertices of diagonal QS. (c) If point G divides the line QR in the ratio 1:2, then find the coordinates of G.

Solution

I can help you with the math problem in the image you've uploaded. It seems to contain three tasks related to a rectangular plot of land with trees and a smaller inner rectangle labeled PQRSPQRS.

Let me summarize and solve each part:

Part (a) - Find the width of rectangle PQRSPQRS

From the diagram, it appears there is a coordinate grid with points marked at each meter along the boundary. The distance between any two adjacent points on the boundary is 1 meter.

Let’s identify the coordinates of P,Q,R,P, Q, R, and SS:

  • Point PP appears to be at (2,8)(2, 8)
  • Point QQ appears to be at (2,4)(2, 4)
  • Point RR appears to be at (6,4)(6, 4)
  • Point SS appears to be at (6,8)(6, 8)

The width of the rectangle PQRSPQRS can be found by calculating the horizontal or vertical distance between the points. The horizontal distance between PP and SS (or QQ and RR) is 62=46 - 2 = 4 meters, and the vertical distance between PP and QQ (or SS and RR) is 84=48 - 4 = 4 meters.

Thus, the width of the rectangle PQRSPQRS is 4 meters.


Part (b) - Find the distance between the vertices of diagonal QSQS

To find the distance between points Q(2,4)Q(2, 4) and S(6,8)S(6, 8), we can use the distance formula: d=(x2x1)2+(y2y1)2d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} Substituting the coordinates of QQ and SS: d=(62)2+(84)2=42+42=16+16=32=42metersd = \sqrt{(6 - 2)^2 + (8 - 4)^2} = \sqrt{4^2 + 4^2} = \sqrt{16 + 16} = \sqrt{32} = 4\sqrt{2} \, \text{meters}

The distance between QQ and SS is 425.664\sqrt{2} \approx 5.66 meters.


Part (c) - If point GG divides the line QRQR in the ratio 1:21:2, find the coordinate of GG

To find the coordinates of a point that divides a line in a given ratio, we use the section formula. The section formula for dividing a line between points (x1,y1)(x_1, y_1) and (x2,y2)(x_2, y_2) in the ratio m:nm:n is: (x,y)=(mx2+nx1m+n,my2+ny1m+n)(x, y) = \left( \frac{m x_2 + n x_1}{m + n}, \frac{m y_2 + n y_1}{m + n} \right) Here, point GG divides line QRQR in the ratio 1:2. The coordinates of QQ are (2,4)(2, 4), and the coordinates of RR are (6,4)(6, 4). Substituting into the section formula: xG=1×6+2×21+2=6+43=1033.33x_G = \frac{1 \times 6 + 2 \times 2}{1 + 2} = \frac{6 + 4}{3} = \frac{10}{3} \approx 3.33 yG=1×4+2×41+2=4+83=123=4y_G = \frac{1 \times 4 + 2 \times 4}{1 + 2} = \frac{4 + 8}{3} = \frac{12}{3} = 4

Thus, the coordinates of point GG are (103,4)(3.33,4)\left( \frac{10}{3}, 4 \right) \approx (3.33, 4).


Summary:

  • (a) The width of rectangle PQRSPQRS is 4 meters.
  • (b) The distance between QQ and SS is 424\sqrt{2} meters or approximately 5.66 meters.
  • (c) The coordinates of point GG are approximately (3.33,4)(3.33, 4).

Let me know if you'd like further clarification or additional details.


Related Questions:

  1. How do you find the length of diagonal PRPR using the distance formula?
  2. What is the area of rectangle PQRSPQRS?
  3. How would you calculate the perimeter of rectangle PQRSPQRS?
  4. If point GG divides PRPR instead of QRQR, what would the coordinates of GG be?
  5. How does the section formula change if the ratio is reversed, i.e., 2:12:1?

Tip: Remember that the section formula can be applied in both 2D and 3D geometry to find the coordinates of a dividing point.

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Math Problem Analysis

Mathematical Concepts

Coordinate Geometry
Distance Formula
Section Formula

Formulas

Distance formula: d = sqrt((x2 - x1)^2 + (y2 - y1)^2)
Section formula: (x, y) = ((mx2 + nx1)/(m+n), (my2 + ny1)/(m+n))

Theorems

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Suitable Grade Level

Grade 10